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Alika [10]
3 years ago
8

Can someone help please?

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Answer:

10

Step-by-step explanation:

3x2 + 2x2 = 10

you multiple they length by two, then the width by two, and then add your two answers together.

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Find the value of x
lbvjy [14]

Answer:

x = 14.5

Step-by-step explanation:

Exterior angle thm

<C = <D

7x - 2 = 9x - 31

7x - 9x = -31 + 2

-2x = -29

x = 14.5

5 0
2 years ago
Here are some photos of my math home work please show some work.
Reika [66]

Answer:

I can answer 2-19.

Step-by-step explanation:

The first equation is x=0.

the second equation has no solution.

4 0
3 years ago
Find the prime factorization of 35
AnnyKZ [126]
<h3>Question:</h3><h3>•Find the prime factorization of 35.</h3>

Answer:

•The Prime Factors of 35 are 1, 5, 7, 35 and its Factors in Pairs are (1, 35) and (5, 7).

<h3>Explanation:</h3>

#Let's Study

#I Hope It's Help

#Keep On Learning

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4 0
2 years ago
Read 2 more answers
How do i solve for x ​
sergiy2304 [10]

Expplanation and Answer:

y=mx−7

Swap sides so that all variable terms are on the left hand side.

mx−7=y

Add 7 to both sides.

mx=y+7

Divide both sides by m.

m

mx

​

=

m

y+7

​

Dividing by m undoes the multiplication by m.

x=

m

y+7

​

3 0
2 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
3 years ago
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