Which one do you need help with
Let n is the number of marbles.
when marbles are equally shared among 6, 7 or 8 students, each time 4 marbles left over.
To find the least number of marbles, first we find out what is the smallest number that can be divided to 6, 7 and 8.
Now you see that 6 and 8 are divisible by 2 but 7 is non- divisible.
if we take LCM of 6, 7 and 8 and find the smallest number.
2 I6,7,8
-------
3,7,4
Now multiply 2,3,7 and 4
2 x 3 x7 x 4 = 168
each time 4 marbles left so
least possible number of marbles in the box = 168 + 4 = 172
U can round 289 to 290 and round 7 to 5 or 10
Answer:
27 =x
Step-by-step explanation:
The two angles are vertical angles and vertical angles are equal
4x+7 = 5(x-4)
Distribute
4x+7 = 5x-20
Subtract 4x from each side
4x+7-4x = 5x-4x-20
7 = x-20
Add 20 to each side
7+20 = x-20+20
27 =x