Answer:
The answer to the above question is x = -5
Ln ( a^(-4) / b^1 c^1 ) =
= ln a ^(-4) - ( ln b + ln c ) =
= - 4 ln a - ln b - ln c =
= - 4 * 2 - 3 - 5 =
= - 8 - 3 - 5 = - 16
Answer:
Solution : 
Step-by-step explanation:
![-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]](https://tex.z-dn.net/?f=-3%5Cleft%5B%5Ccos%20%5Cleft%28%5Cfrac%7B-%5Cpi%20%7D%7B4%7D%5Cright%29%2Bi%5Csin%20%5Cleft%28%5Cfrac%7B-%5Cpi%20%5C%3A%7D%7B4%7D%5Cright%29%5Cright%5D%5C%3A%5Cdiv%20%5C%3A2%5Csqrt%7B2%7D%5Cleft%5B%5Ccos%20%5Cleft%28%5Cfrac%7B-%5Cpi%20%5C%3A%5C%3A%7D%7B2%7D%5Cright%29%2Bi%5Csin%20%5Cleft%28%5Cfrac%7B-%5Cpi%20%5C%3A%5C%3A%5C%3A%7D%7B2%7D%5Cright%29%5Cright%5D)
Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,
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As you can see your solution is the last option.
6(2x - 11) + 15 = 21
First step use distributive property on the left side to remove the parenthesis, to do this multiply 6 by each term inside the parenthesis:
12x - 66 + 15 = 21
Second step, simplify the left side by combining the like terms:
12x - 51 = 21
Third step, add 51 to both sides of the equation:
12x = 72
Last step, divide both sides by 12:
x = 72/12
x = 6
