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3 years ago

- x / 3 = 6 ( solving linear equations )

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

8 0

-x/3=6
3*-x/3=6*3
-x=18

labwork [276]3 years ago

6 0

-x / 3 = 6

Multiply each side by 3 : -x = 18

Multiply each side by -1 : <em> x = -18</em>

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Black_prince [1.1K]

Answer:

The answer is obviously (2³$&8*9ⁿ+⁶7⅞)

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2 years ago

Take 25 points please help me!!!!<br>one example,for the matrix skew-Hermitian

GrogVix [38]

Answer:

Una matriz hermitiana, o también llamada matriz hermítica, es una matriz cuadrada con números complejos que tiene la característica de ser igual a su traspuesta conjugada.

A=A^*

Donde A^* es la matriz traspuesta conjugada de A.

Step-by-step explanation

Ejemplo de matriz hermitiana de orden 2×2

₍ 5............. 3+7i₎

₍3-7i .............2

₎

Ejemplo de matriz hermitiana de dimensión 3×3

(3............2-i......-5i)

(2+i............0.....9-5i)

(5i.........9+5i.....6)

5 0

3 years ago

Find the dimensions of a rectangle (in m) with area 1,000 m2 whose perimeter is as small as possible. (Enter the dimensions as a

Amanda [17]

The perimeter of the rectangle is the sum of its dimensions

The dimensions that minimize the perimeter are $\mathbf{10\sqrt{10 },10\sqrt{10 }}$

The area is given as:

$\mathbf{A = 1000}$

Let the dimension be x and y.

So, we have:

$\mathbf{A = xy = 1000}$

Make x the subject

$\mathbf{x = \frac{1000}{y}}$

The perimeter is calculated as:

$\mathbf{P = 2(x + y)}$

Substitute $\mathbf{x = \frac{1000}{y}}$

$\mathbf{P = 2(\frac{1000}{y} + y)}$

Expand

$\mathbf{P = \frac{2000}{y} + 2y}$

Differentiate

$\mathbf{P' = -\frac{2000}{y^2} + 2}$

Set to 0

$\mathbf{ -\frac{2000}{y^2} + 2 = 0}$

Rewrite as:

$\mathbf{ -\frac{2000}{y^2} = -2}$

Divide both sides by -1

$\mathbf{\frac{2000}{y^2} = 2}$

Multiply y^2

$\mathbf{2000 = 2y^2}$

Divide by 2

$\mathbf{1000 = y^2}$

Take square roots of both sides

$\mathbf{y = \sqrt{1000 }}$

$\mathbf{y = 10\sqrt{10 }}$

Substitute $\mathbf{y = \sqrt{1000 }}$ in $\mathbf{x = \frac{1000}{y}}$

$\mathbf{x = \frac{1000}{\sqrt{1000}}}$

$\mathbf{x = \sqrt{1000}}$

$\mathbf{x = 10\sqrt{10 }}$

Hence, the dimensions that minimize the perimeter are $\mathbf{10\sqrt{10 },10\sqrt{10 }}$