Answer: 20
Step-by-step explanation:
Answer:
x = (-10)/43
Step-by-step explanation:
Solve for x:
91 x = 5 x - 20
Subtract 5 x from both sides:
91 x - 5 x = (5 x - 5 x) - 20
91 x - 5 x = 86 x:
86 x = (5 x - 5 x) - 20
5 x - 5 x = 0:
86 x = -20
Divide both sides of 86 x = -20 by 86:
(86 x)/86 = (-20)/86
86/86 = 1:
x = (-20)/86
The gcd of -20 and 86 is 2, so (-20)/86 = (2 (-10))/(2×43) = 2/2×(-10)/43 = (-10)/43:
Answer: x = (-10)/43
Answer:
n+3
Step-by-step explanation:
hello :
1/2(2n + 6) = (1/2)(2n) +(1/2)(6)
the expression is equivalent to 1/2(2n + 6) is n+3
<h2>
Explanation:</h2>
Hello! Remember you have to write complete questions in order to get good and exact answers. I'll assume that you have a circle X having two tangent lines that intersect at a point outside the circle. From geometry, we know that from any point outside a circle, two tangents to that circle are always congruent to each other if they meet at the mentioned point. So if the point of intersection is called Z, and a line is tangent to the circle at a point Y, ZY must be equal to ZW because ZW is tangent to the same circle at point W and meets ZY at a point outside the circle, then it is true that:
![\overline{ZY}=\overline{ZW} \\ \\ \boxed{\overline{ZY}=3}](https://tex.z-dn.net/?f=%5Coverline%7BZY%7D%3D%5Coverline%7BZW%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B%5Coverline%7BZY%7D%3D3%7D)
So <em>the ZY must be equal 3 in order for ZY to be tangent to circle X at point Y</em>