The table shows the number of words Marla can type in a given time.

When would it be more useful to represent a proportional relationship with a graph rather than an equation

kolezko [41]

It would be <span>more useful to represent a proportional relationship with a graph rather than an equation when you need to compare two things visually. The graph gives you a clearer idea than am equation. I hope that this is the answer that you were looking for and it has actually come to your great help.</span>

5 0

3 years ago

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A number k increased by 7 =34

grin007 [14]

Let's set up this problem.
k+7=34
Subtract k from both sides.
k=27

5 0

3 years ago

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Weber's Mail Manufacturing is a company that produces chain mail. Their most popular product is saw-cut metal links that hobbyis

mariarad [96]

Answer:

Their expenses and sales will both equal at 200 ounces.

Step-by-step explanation:

This can be determined using the break-even point in ounce formula as follows:

Break even point in ounce = Fixed cost / Contribution per ounce

Where;

Fixed cost = Advertising = $600

Contribution per ounce = Selling price per ounce - Cost per ounce = $4 - $1 = $3

Substituting the values into equation (1), we have:

Break even point in ounce = $600 / $3 = 200 ounces

Therefore, their expenses and sales will both equal at 200 ounces.

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B2%7D%7B3%7D%28x-4%29%28x%2B5%29%3D1%5Cimplies%20%5Ccfrac%7B2%28x-4%29%28x%2

adell [148]

Answer:

x = - 6 3/10

We need to show at least two of these in workings including one in simplified format.

x = - 63/10 (minus in front of whole fraction)

mixed number form x = -6 3/10 (is simplified answer)

decimal form x = -6.3 (is simplified answer)

Step-by-step explanation:

Just in case you ever need to write these in ans search answers already answered in same format.

You can;

Go to upper right corner and click the three dots : another menu opens.

Click the summation sign (4th from left) : you are now in math mode until you deselect it (which sometimes happens automatically). Type a^{2} and it will look like a2 .

Note : the brackets { and } aren’t necessary when your exponent is a natural number between 0 and 9, both included.

However, when you want to type e.g. a15 , you need to place them, because otherwise you will get a15 .

it will look in same way as we are taught with a pen, its the stupid copy paste thing hit and miss if it works on messages here, Obviously it didnt work when i copied just now.

Adding a Range of Cells Using the Summation Button

The Summation button will copy a formula that calculates the sum of the selected numeric cells to the clipboard.

For alphanumeric cells, clicking the Summation button will concatenate the text of the selected cells.

Select the cells by dragging the mouse over the selected area or dragging while holding Alt.

On the Document tab, click Summation.

Position the insertion point in the total cell.

On the Home tab, click Paste.

The Equation bar displays the addition of all cells in the selection.

Note: Only Numeric cells can be summed. Alphanumeric cells will have their text concatenated.

6 0

3 years ago

The figure below shows two triangles EFG and KLM.

grandymaker [24]

A right triangle is a triangle that has a right angle of 90 degrees. In this exercise, we have two of this type of triangles. To solve this problem, we will apply some properties of triangles, so:

1. Which step can be used to prove that triangle EFG is also a right triangle?

To prove this, we need to use Pythagorean Theorem. So, for triangle EGF, if the formula:

$c^{2}=a^{2}+b^{2}$

is true, then EFG is also a right triangle. The steps are:

Square a

Square b

Square c

If the sum of the square of a and the sum of the square of b equals the square of c, then this is a right triangle.

2. Prove that the sum of a and c is greater than b.

We need to prove that:

$a+c>b$

From trigonometry, we know that:

$a=c \times sin(\theta) \\ \\ b=c \times cos(\theta) \\ \\ where \ \theta=\angle EFG \\ \\$

By substituting these values in the previous inequality:

$c \times sin(\theta)+c>c \times cos(\theta) \\ \\ Since \ c>0 \\ \\ sin(\theta)+1>cos(\theta) \\ \\ 1>cos(\theta)-sin(\theta)$

Since $\theta$ is an angle greater than 0 and less than 90 degrees, $cos(\theta) \ and \ sin(\theta)$ are numbers between 0 (greater than) and 1. Therefore, this inequality is always true. So, the statement has been proved.

3. Prove that the sum of a and b is greater than c.

We need to prove that:

$a+b>c$

Applying the same reasoning as in 2:

$c \times sin(\theta)+c \times cos(\theta)>c \\ \\ Since \ c>0 \\ \\ sin(\theta)+cos(\theta)>1$

This inequality is always true. So, the statement has been proved.

4. Prove that triangles are congruent by SSS property and hence angle EGF is equal to angle KML.

SSS means that we know the three sides of the triangle and want to find the missing angles. For ΔEGF, we know the three sides, and for KML, since this is a right triangle KL = c, therefore the corresponding sides of these two triangles are equal. Accordingly, these two triangles are congruent by SSS and angle EGF is equal to angle KML.

5. Prove that the ratio of EF and KL is greater than 1 and hence the triangles are similar by AA postulate.

The ratio of EF and KL is:

$\frac{EF}{KL}$

The statement is true if and only if EF > KL. Then, according to AA postulate, two triangles are similar if they have two corresponding angles congruent. So:

EGF is congruent to KML and equals 90 degrees
GEF is congruent to MKL
EFG is conguent to KLM

Accordingly, the triangles are similar.

3 0

3 years ago

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