$x=3$ I think that’s it... try that
Answer:
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Step-by-step explanation:
Answer
The length of the rectangle is 20 inches, and the width of the rectangle is 4 inches if the table runner has an area of 80 square inches. The length and width of the table runner are whole numbers. The length is 5 times greater than the width.
<h3>What is the area of the rectangle?</h3>
It is defined as the space occupied by the rectangle which is planner 2-dimensional geometry.
The formula for finding the area of a rectangle is given by:
Area of rectangle = length × width
The area of the table runner = 80 square inches
Let's assume the length of the rectangle is L and the width is W
Then L = 5×W ...(1)
L×W = 80 ...(2)
Put the value of L in the equation (2)
5W(W) = 80
5W² = 80
W² = 16
W = ±4
Width cannot be negative.
W = 4 inches putting this value in the equation (1)
L = 5(4) = 20 inches
Thus, the length of the rectangle is 20 inches, and the width of the rectangle is 4 inches if the table runner has an area of 80 square inches. The length and width of the table runner are whole numbers. The length is 5 times greater than the width.
Learn more about the area here:
brainly.com/question/14383947
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Answer:
x = 4
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
20x+5−0=5x+(32.5)(2)
20x+5+0=5x+65
(20x)+(5+0)=5x+65(Combine Like Terms)
20x+5=5x+65
20x+5=5x+65
Step 2: Subtract 5x from both sides.
20x+5−5x=5x+65−5x
15x+5=65
Step 3: Subtract 5 from both sides.
15x+5−5=65−5
15x=60
Step 4: Divide both sides by 15.
15x
15
=
60
15
x=4
Hope this helps!
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