Answer : The concentration of
and
are
and
respectively.
Solution : Given,
pH = 4.10
pH : pH is defined as the negative logarithm of hydronium ion concentration.
Formula used : ![pH=-log[H_3O^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH_3O%5E%2B%5D)
First we have to calculate the hydronium ion concentration by using pH formula.
![4.10=-log[H_3O^+]](https://tex.z-dn.net/?f=4.10%3D-log%5BH_3O%5E%2B%5D)
![[H_3O^+]=antilog(-4.10)](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3Dantilog%28-4.10%29)
![[H_3O^+]=7.94\times 10^{-5}](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D7.94%5Ctimes%2010%5E%7B-5%7D)
Now we have to calculate the pOH.
As we know, 


Now we have to calculate the hydroxide ion concentration.
![pOH=-log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E-%5D)
![9.9=-log[OH^-]](https://tex.z-dn.net/?f=9.9%3D-log%5BOH%5E-%5D)
![[OH^-]=antilog(-9.9)](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3Dantilog%28-9.9%29)
![[OH^-]=1.258\times 10^{-10}](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.258%5Ctimes%2010%5E%7B-10%7D)
Therefore, the concentration of
and
are
and
respectively.
Its condensation
the vapour has a lot of kinetic energy but if it cools down it loses that energy and condenses into a liquid
hope that helps
Answer:
Mass = 427.05 g
Explanation:
Given data:
Formula units of sodium chloride = 4.38 ×10²⁴
Mass of NaCl = ?
Solution:
One mole contain formula units = 6.022 ×10²³
4.38×10²⁴ formula units × 1mol /6.022 ×10²³ formula units
0.73 ×10¹ mol
7.3 mol
Mass of NaCl:
Mass = number of moles × molar mass
Mass = 7.3 mol × 58.5 g/mol
Mass = 427.05 g
Answer:
It does this by using a thermal conductor (usually metal) to carry heat away from the processor into fins that expose a high amount of surface area to moving air. This allows the air to be heated, thus cooling the heat sink and the processor as well.
Answer:
The stronger electrolyte is the HCl
Explanation:
Stronger electrolyte are the ones, that in water, completely dissociates.
HCl(aq) → H⁺(aq) + Cl⁻(aq)
HCl(aq) + H₂O(l) → H₃O⁺ (aq) + Cl⁻(aq)
Both are acids, they bring protons to medium but the hydrochloric completely dissociates.
HF (aq) + H₂O(l) ⇄ H₃O⁺(aq) + F⁻(aq) Ka
In the dissociation of weak electrolytes, they ionize but at the same time they bond again, so the reaction is always kept in equilibrium.