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shtirl [24]
3 years ago
6

Consider the following data:

Chemistry
2 answers:
VikaD [51]3 years ago
8 0

∆H ° rxn =-2855.56 kJ

<h3>Further explanation</h3>

Given

ΔHf CO₂ = -393.5 kJ/mol

ΔHf H₂O = -241.82 kJ/mol

ΔHf  C₂H₆ = - 84.68 kJ/mol

Reaction

2C2H6(g) + 7O2(g) -> 4CO2(g) + 6H2O(g)

Required

ΔHrxn=

Solution

<em>∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants) </em>

∆H ° rxn = (4.-393.5+6.-241.82)-(2.-84.68)

∆H ° rxn = (-1574-1450.92)-(-169.36)

∆H ° rxn =-3024.92+169.36

∆H ° rxn =-2855.56 kJ

Dafna1 [17]3 years ago
5 0

Answer:

-2856 kJ

Explanation:

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