All categories

2 years ago

Consider the following data:

Chemistry

2 answers:

VikaD [51]2 years ago

8 0

∆H ° rxn =-2855.56 kJ

<h3>Further explanation</h3>

Given

ΔHf CO₂ = -393.5 kJ/mol

ΔHf H₂O = -241.82 kJ/mol

ΔHf C₂H₆ = - 84.68 kJ/mol

Reaction

2C2H6(g) + 7O2(g) -> 4CO2(g) + 6H2O(g)

Required

ΔHrxn=

Solution

<em>∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants) </em>

∆H ° rxn = (4.-393.5+6.-241.82)-(2.-84.68)

∆H ° rxn = (-1574-1450.92)-(-169.36)

∆H ° rxn =-3024.92+169.36

∆H ° rxn =-2855.56 kJ

Dafna1 [17]2 years ago

5 0

Answer:

-2856 kJ

Explanation:

You might be interested in

“What types of friction occur between your bike tires and the ground when you ride over cement, through a puddle, and when you a

Kruka [31]

The right answer is= <span>rolling, fluid, and sliding</span>

4 0

2 years ago

The results of a classroom group activity performed to test the acidic or basic nature of two substances are shown in the table.

zvonat [6]

Substance a is a base, and substance b is an acid

4 0

2 years ago

Which hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine?

arsen [322]

The highlighted atoms have sp2 - sp3 hybridization. The highlighted atoms are carbon and nitrogen as shown.

The structure of Xanthine is shown in the image attached to this answer. The indicated atoms are Carbon and nitrogen as shown. Let us remember that hybridization has to do with the mixing of atomic orbitals to form appropriate hybrid orbitals that are suitable for overlap with orbitals of other atoms.

The highlighted carbon atom is sp2 hybridized because it has a carbon nitrogen double bond while the highlighted nitrogen atom is sp3 hybridized. Therefore, the highlighted atoms have sp2 - sp3 hybridization.

Learn more: brainly.com/question/22824409

4 0

2 years ago

What happens in the redox reaction below? Select all that apply.

vladimir2022 [97]

Answer:

B- Sodium loses an electron.

D- Fluorine gains an electron.

Sodium is oxidized.

Explanation:

The reaction equation is given as:

Na + F → NaF

In this reaction, Na is the reducing agent. It loses an electron and then becomes oxidized. By so doing, Na becomes isoelectronic with Neon.

Fluorine gains the electron and then becomes reduced. This makes fluorine also isoelectronic with Neon.

This separation of charges on the two species leads to an electrostatic attraction which forms the ionic bonds.

6 0

2 years ago

I can be found in the 4th period on the periodic table.

Rainbow [258]

Vanadium (V)

Vanadium is the only one in the 4th period here so

4 0

2 years ago