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Elanso [62]
3 years ago
7

Where are the most reactive metals on the periodic table? to the far right in the middle at the top to the far left

Chemistry
2 answers:
frez [133]3 years ago
7 0
Most reactive are on the far left.
Murrr4er [49]3 years ago
3 0

Answer: Option (d) is the correct answer.

Explanation:

Metals are the substances that have more number of electrons. In order to attain stability, metals lose electrons and thus becomes positively charged.

A metal with less number of valence electrons will be more reactive because it will readily lose its valence electrons to become stable.

For example, atomic number of potassium is 19 with electronic distribution is 2, 8, 8, 1. Potassium is a group I element. So, to become stable it will lose its 1 extra electron readily.

Therefore, we can conclude that the most reactive metals on the periodic table are placed on to the far left.

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A solution that is a 4 on pH scale is a
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A pH scale runs from 1 to 14 with 7 being neutral.

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What is the volume of 40.0 grams of argon gas at STP ?
MrRa [10]

Answer:

24.9 L Ar

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Aqueous Solutions</u>

  • States of Matter

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 40.0 g Ar

[Solve] L Ar

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Ar - 39.95 g/mol

[STP] 22.4 L = 1 mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 40.0 \ g \ Ar(\frac{1 \ mol \ Ar}{39.95 \ g \ Ar})(\frac{22.4 \ L \ Ar}{1 \ mol \ Ar})
  2. [DA] Divide/Multiply [Cancel out units]:                                                         \displaystyle 24.9235 \ L \ Ar

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

24.9235 L Ar ≈ 24.9 L Ar

5 0
3 years ago
V2 = (P1 × V1 × T2) (P2 × T1) A gas with a beginning pressure of 2 atm at a temperature of 300 K has a volume of 20 ml. What wil
rusak2 [61]

6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

V_1=20 ml

T_1=3

P_1=2 atm

T_2=200 K

P_2=4 atm

V_2=?

Using equation:

V_2 = \frac{P_1 X V_1 XT_2}{P_2 X T_1}

V_2 =\frac{2 atm  X 20 ml X200 K}{4 atm  X 300 K}

V_2 = 6.6 ml

Hence, 6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

Learn more about the ideal gas equation here:

#SPJ1

6 0
2 years ago
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