The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.
A(t) = A(o) (1/2)^(t/d)
where t is the certain period of time. Substituting the known values,
A(t) = (20 mg)(1/2)^(85.80/14.30)
Solving,
A(t) = 0.3125 mg
Hence, the answer is 0.3125 mg.
Answer:
Idk if this is right but i hope it helps... sorry if it's wrong
Explanation:
A. 0.25 g/mL
Because 6/24 is 0.25
Answer:
148 grams of relative atomic mass
Explanation:
magnesium atomic mass : 24
nitrogen : 14
oxygen : 16
24 × 1
14 × 1 × 2
16 × 3 × 2
24 + 28 + 80 = 148 grams
I think it’s 7.41 because you count up all the atoms and find out how many are x (the large grey ones) and you do 2/27 x 100 which gives you 7.41 :) (sorry if i counted wrong it’s kinda hard)