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3 years ago

HELP ASAP PLEASE.

Mathematics

2 answers:

nordsb [41]3 years ago

5 0

The range of the primary phone data is 0.28.
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.

To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28

To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73

To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12

To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6

The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48

Sunny_sXe [5.5K]3 years ago

5 0

Answer:

The range of data usage for the primary phone is 0.28 gigabytes.

The range of data usage for the secondary phone is 0.73 gigabytes.

The median data usage of the secondary phone is 0.48 gigabytes greater than the median data usage of the primary phone.

Step-by-step explanation:

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Artyom0805 [142]

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Step-by-step explanation:

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Step-by-step explanation:

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