The range of the primary phone data is 0.28. The range of the secondary phone data is 0.73. The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.
To find the range of the primary phone data, subtract the largest and the smallest values: 0.35 - 0.07 = 0.28
To find the range of the secondary phone data, subtract the largest and the smallest values: 1.18 - 0.45 = 0.73
To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value: 0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12
To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value: 0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6
The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
P of selecting point on the shaded region = shaded area/whole area <span>P( selecting point on the shaded ) = ( the four shaded circles ) / the whole square </span> <span>P of selecting point on the shaded = ( 4 * ( π * r^2 ) )/ x^2 </span> <span>P of selecting point on the shaded = ( 4 * ( π * (x/4)^2 ) )/ x^2 </span> <span>P of selecting point on the shaded = ( 4 * ( π * x^2/16 ) )/ x^2 </span> <span>P of selecting point on the shaded = ( π * x^2/4 )/ x^2 </span> <span>P of selecting point on the shaded = x^2( π/4 )/ x^2 </span> <span>P( selecting point on the shaded ) = π/4 ≈ 0.7854 ≈ 79% =80% D is right option hope this helps</span>
Lets say that you flipped the smaller triangle to be facing the same way as the bigger triangle. To find the X side, we need to do 4.5/1.2 = 1.75. which is the difference between the sides. So then we do 1.75 x 0.8 = 3.
Sorry if I couldn't explain well enough, which is not something I'm good at. I hope you get the question right! Glad I could help! :)
