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galben [10]
2 years ago
14

Explain the main difference between using a list and a table to organize information in a web page?

Computers and Technology
1 answer:
Ratling [72]2 years ago
5 0

Answer:

A table is fine till we need rows and columns. However, the list is quite more flexible. Hence, the table is always going to be a great choice when the data needs to be expressed as a table. However, if we want a more flexible view for a list of products or items with quite a long list of properties. Also, we can have any level of indented lists within the list. This can be done with the help of tabs, and bullets and numbering. Both ordered and unordered lists are possible. And that proves lists are more flexible. And the main purpose of the table is the row and column type of formatting on the web page, where we create a table and then hide the borders.

Explanation:

Please check the answer section.

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A_________is an orderly collection of fact & information.
sammy [17]

Answer:

C. Database

Explanation:

4 0
3 years ago
Developed by Frank Vahid. Write a program using integers usernum and x as input, and output usernum divided by x four times. For
OleMash [197]

Answer:

Explanation:

Let's do this in Python. We will loop through 4 times, each of the loop would compute the dividend, store it as string in a result variable and finally print the result on the same line:

def divide_4_times(user_num, x):

    result = ''

    for i in range(4):

         user_num /= x

         result += (' ' + str(user_num))

   print(result)

7 0
3 years ago
How come the scroll bar on the PA emojis only appears sometimes? how do I make it appear?
astraxan [27]
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3 years ago
A computer program is tested by 5 independent tests. If there is an error, these tests will discover it with probabilities 0.1,
Svetllana [295]

Answer:

0.8488

Explanation:

Let E =error found by test 1

Let F=error found by test 2

Let G=error found by test 3

Let H=error found by test 4

Let I= error found by test 5

Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5

therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5

Tests are independent P(not E & not F &not G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512

P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488

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3 years ago
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The answer of this question is bios software applications it detects errors in system configuration?
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