Answer:
Add the hex value to the appropriate base-
16 place-value column: 2 in the 16 column; D in the 1 column.
Work out the hex digits and their representation in denary-
2 = 2 in denary; D = 13 in denary.
Multiply with the place value: 2 x 16 = 32; 13 x 1 = 13.
Add the values together: 32 + 13 = 45 in denary.
Explanation:
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The menu that allow you to add content to the table of contents is Add Text.
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Answer:
31 bits.
Explanation:
Given, total number of registers = 55
Total instructions = 60
Size of memory = 16 KB
Now, no of registers are 55. We find the next greater or equal power of 2 which is 64 = 26. Hence, 6 bits are required to represent a register operand.
Number of instructions = 60. We find the next greater or equal power of 2 which is 64 = 26. Hence, 6 bits are required to represent a instruction.
Size of memory = 64 KB = 26 * 210 * 23 bits = 219 bits. Hence, 19 bits are required to represent a memory location.
Now, an instruction has 2 parts, opcode and operand. As given there are only two address instructions which are memory operand and register operand.
Hence, total bits would be: 6 bits (opcode) + 6 bits (register operand) + 19 (memory operand) = 31 bits.
