All categories

3 years ago

Carol gave a 15 deposit on a diamond bracelet. The deposit was $73.50. What was the cost of the bracelet?

Mathematics

1 answer:

leva [86]3 years ago

4 0

You probably meant 15%
if so,

$\frac{73.50}{.15} = 490$

You might be interested in

9. Alicia Martin's savings account has a principle of $1,200. It earns 6% interest compounded quartly

zavuch27 [327]

Answer:

$9) \$1236.27\,10)\,\$6451.07\, 11)\,\$10,152.87 \,12)\,\$907.95 \,13)\,\$4957.69$

Step-by-step explanation:

9) Since Alicia Martin's savings earns 6% quarterly for two quarters then:

$A=P(1+\frac{r}{n})^{nt}$ ⇒ Amount (A), Principle (P), rate (r) in decimal form, number of compoundings (n) a year and t, in year or its fractions.

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=1200(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A=\$1236.27$

10) Aubrey Daniel's case:

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=5725(1+\frac{0.04}{4})^{4*3}\Rightarrow A\approx \$6451.07$

11) As for Angelo, similarly to Alicia.

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=9855(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$10,152.87$

12) Simpson's. For semiannual n=2

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=860(1+\frac{0.055}{2})^{2*1}\Rightarrow A\approx \$907.95$

13) Jana Lacey amount:

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=4860(1+\frac{0.04}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$4957.69$

6 0

3 years ago

How many times does 20 go into 168?

ch4aika [34]

The answer:

8 times

Explanation:

If you divide 168 by 20, you get 8.4, and the whole number is 8 so that’s the answer.

7 0

3 years ago

Read 2 more answers

What is the answer???

Greeley [361]

Answer:

Angles in ascending order:

Q, R, S

Step-by-step explanation:

The side with the biggest number also has the biggest angle degree. The side with the smallest number also has the smallest angle degree.

6 0

3 years ago

Read 2 more answers

In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1 - P( x ≤ 5 )

P ( x ≥ 6) = 1 - 0.9707

P ( x ≥ 6) = 0.0293

4 0

2 years ago

Elimination method: ax+by=r, -bx+cy=s

Alex17521 [72]

$\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]$

Isolate x for $ax+by=r$

$x= \frac{r-by}{a} ; a \neq 0$

Subsititute $x= \frac{r-by}{a}$

$-b \frac{r-by}{a} +cy=s$

Isolate r for : $-b \frac{r-by}{a}+cy=s$

$r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0$

For x : $\frac{r-by}{a}$

Subsititute r = $- \frac{as-acy-b^2y}{b}$

$x= -\frac{as-acy-b^2y}{b}/a$

$x = \frac{cy-s}{b}$

The solutions to the system of equations are:

$r= -\frac{as-acy-b^2y}{b}$ and <span> $x = \frac{cy-s}{b}$
</span>
hope this helps!

3 0

2 years ago