Question

The sum of theee consecutive numbers is 90. what is the smallest of the three numbers?

Answer 1

29

Note that consecutive numbers have a difference of 1 between them.

let n be the smallest integer then the three integers can be expressed as

n, n + 1 , n + 2

the sum is then

n + n + 1 + n + 2 = 90

3n + 3 = 90

subtract 3 from both sides of the equation

3n = 90 - 3 = 87

divide both sides by 3

n = $\frac{87}{3}$ = 29

the three integers are 29, 30, 31 → the smallest is 29