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2 years ago

Please help me now plz I will mark you brainliest

Mathematics

1 answer:

Masteriza [31]2 years ago

7 0

Answer:

x= 12 units.

Step-by-step explanation:

To solve this equation, we can find each half of the base using the Pythagorean theorem. We will use 'x' as denoting each HALF of the base:

45= 3²+x²

Subtracting from both sides will give us:

36= x²

x=6.

However, the base in this problem is '2x' because 'x' is HALF of the base.

2(6)= 12 units.

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If the first number is increased by 7 and the second number is reduced by 6 times, the sum of these numbers is 29.

Marta_Voda [28]

Answer:

First number = 20

Second number = 12

Explanation:

Let the 1st number be x

Let the 2nd number be y

=====================

Condition 1

$\sf \rightarrow x + 7 + \dfrac{y}{6} = 29$

$\rightarrow \sf x=-\dfrac{y}{6}+22$

=====================

Condition 2

$\rightarrow \sf 2y - (x - 5) = 9$

$\rightarrow \sf x = 2y -4$

=====================

Substitute equations

$\rightarrow \sf -\dfrac{y}{6}+22 = 2y-4$

$\rightarrow \sf y=12$

=====================

Find value of 1st number

$\rightarrow \sf x = 2y - 4$

$\sf \rightarrow x = 2(12) - 4$

$\rightarrow \sf x = 20$

7 0

1 year ago

A room contains three urns: u1, u2, u3. u1 contains 3 red and 2 yellow marbles. u2 contains 3 red and 7 yellow marbles. u3 conta

Archy [21]

Answer:

$\dfrac{11}{30}$

Step-by-step explanation:

Urn U1: 3 red and 2 yellow marbles, in total 5 marbles.

The probability to select red marble is $\dfrac{3}{5}=0.6.$

Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

The probability to select red marble is $\dfrac{3}{10}=0.3.$

Urn U1: 1 red and 4 yellow marbles, in total 5 marbles.

The probability to select red marble is $\dfrac{1}{5}=0.2.$

The probability to choose each urn is the same and is equal to $\frac{1}{3}.$

Thus, the probability that the marble is red is

$\dfrac{1}{3}\cdot 0.6+\dfrac{1}{3}\cdot 0.3+\dfrac{1}{3}\cdot 0.2=\dfrac{1.1}{3}=\dfrac{11}{30}.$

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ankoles [38]

Answer:

Yes, it passes the vertical line test

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This graph has a one to one correspondence and will pass the vertical line test, there fore it is a function

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Andrei [34K]

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krok68 [10]

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