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3 years ago

Need answer please help

Mathematics

2 answers:

ki77a [65]3 years ago

7 0

Answer:

- 2/5

Step-by-step explanation:

PtichkaEL [24]3 years ago

3 0

Answer:

-2/5

Step-by-step explanation:

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AD , BD , and CD are angle bisectors of the sides of △ABC . BE=12 m and BD=20 m.

suter [353]

The answer is 16

And also , can people please stop posting did you get the answer yet, just so you could get the points. They only take two answers, and that's a waste of somebody who could've answered or helped.

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3 years ago

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8751 million as a number

Galina-37 [17]

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3 years ago

The domain of f(x) = 7x + 4 is {-1 < x < 4}. Which integer is not in the range?

guajiro [1.7K]

Answer:

1. all of them are in the range

Step-by-step explanation:

Since -1 < x < 4

then -1 (7) < 7x < 7(4)

- 7 < 7x < 28

-7 + 4 < 7x + 4 < 28 + 4

-3 < 7x + 4 < 32

SInce all the options are within the range between -3 and 32 then the answer is 1.

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3 years ago

Six bakers use a total of 12x - 3.6 pounds of flour each hour. If each baker uses the same amount of flour, find an expression f

sergejj [24]

74p7.673280 + 5473.8t9p4 - 78^6 = 56yu342io.65934

5 0

3 years ago

For the cost function, find the marginal cost at the given production level x. State the units of measurement. (All costs are in

baherus [9]

Answer:

The marginal cost at the given production level is $49.9.

Step-by-step explanation:

The marginal cost function is expressed as the first derivative of the total cost function with respect to quantity (x).

We have that the cost function is given by

$C(x) = 15000 + 50x + \frac{1000}{x}$

So, we need the derivative and then we’ll need to compute the value x = 100 of the derivative.

$C'(x)=\frac{d}{dx}\left(15000+50x+\frac{1000}{x}\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\C'(x)=\frac{d}{dx}\left(15000\right)+\frac{d}{dx}\left(50x\right)+\frac{d}{dx}\left(\frac{1000}{x}\right)\\\\C'(x)=0+50-\frac{1000}{x^2}\\\\C'(x)=50-\frac{1000}{x^2}$

When x = 100, the marginal cost is

$C'(100)=-\frac{1000}{100^2}+50\\\\C'(100)=\frac{499}{10}=49.9$

6 0

3 years ago