Question

I'm just confused on how to start this first of all and then get the right answer

Answer 1

Remember
$\frac{ \sqrt{x} }{ \sqrt{y} } = \sqrt{ \frac{x}{y} }$
and
$\frac{x^m}{x^n}=x^{m-n}$
and
$\sqrt[n]{x^m}=x^ \frac{m}{n}$
and
$\sqrt{ab}=( \sqrt{a})( \sqrt{b} )$

$\frac{ \sqrt{6x^{11}y^7} }{ \sqrt{5x^3y^2} } = \sqrt{ \frac{6x^{11}y^7}{5x^3y^2} }$=
$\sqrt{ (\frac{6}{5} )( \frac{x^{11}}{x^3} } )( \frac{y^7}{y^2}) }$=$\sqrt{ (\frac{6}{5})(x^8)(y^5) }$=$( \sqrt{ \frac{6}{5} } )( \sqrt{x^8})( \sqrt{y^5})$=$\sqrt{ (\frac{6}{5})(x^ \frac{8}{2})(y^ \frac{5}{2})$=$( \sqrt{ \frac{6}{5} } )(x^4)(y^2 \sqrt{y})$=$x^4y^2 \sqrt{ \frac{6y}{5} }$