Answer:
Yes
Step-by-step explanation:
Because they are the same equations, just flipped. hope this helped
A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer:
Translated how?
Step-by-step explanation:
Answer:
Some of the possible factorizations of the monomial given are:
Step-by-step explanation:
To factorize the monomia you need to express it as a product of two or more monomials. Therefore, you must apply the proccedure shown below:
- Descompose into prime numbers:
- Then, keeping on mind that, according to the Product of powers property, when you have two powers with equal base you must add the exponents, you can make several factorizations. Below are shown some of the possible factorizations of the monomial given:
Answer:
f/g at t =3 will be 9/8
d/ddx(f(x)/g(x))=f'(x)d(x)-f(x)g'(x)/(g'(x))^2
rate of change=(6*8)+(9*9)/9^2
rate of change =43/27=1.5925
