First, we have
s1/r1 = s2/r2
The question also states the fact that
s/2πr = θ/360°
Rearranging the second equation, we have
s/r = 2πθ/360°
Then we substitute it to the first equation
s1/r1 = 2πθ1/360°
s2/r2 = 2πθ2/360°
which is now
2πθ1/360° = 2πθ2/360°
By equating both sides, 2π and 360° will be cancelled, therefore leaving
θ1 = θ2
Let's say you want to compute the probability
where
converges in distribution to
, and
follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing
such that its mean and variance are the same as those for
.
Example: If
is binomially distributed with
and
, then
has mean
and variance
. So you can approximate a probability in terms of
with a probability in terms of
:
where
follows the standard normal distribution.
Answer:
14/15
Step-by-step explanation:
simple
3/5 + 1/3= 14/15
Answer:D
Step-by-step explanation:
Answer:
a = - 1, b = - 3, c = - 5, d = - 6
Step-by-step explanation:
Substitute the appropriate values of x into the equation and evaluate
x = - 3 : y = - (- 3) - 4 = 3 - 4 = - 1 → a
x = - 1 : y = - (- 1) - 4 = 1 - 4 = - 3 → b
x = 1 : y = - 1 - 4 = - 5 → c
x = 2 : y = - 2 - 4 = - 6 → d