Answer:
Solution given:
m∠ADB=(4x−12)°
m∠CDB=(3x+6)°
m∠ADC =?
Since diagonal BD bisect the angle <ADC
so
m∠ADB= m∠ADC
(4x-12)°=(3x+6)°
4x-3x=6-12
x=12+6
x=18°
again.
<ADB=m∠ADB+ m∠ADC=4×18-12+3×18+6=120°
So
<u>the m∠</u><u>ADC</u><u> </u><u>=</u><u>1</u><u>2</u><u>0</u><u>°</u>
Answer:
Step-by-step explanation:
6x2 + 5x - 4
6x2 + 8x - 3x - 4
2x(3x + 4) - 1(3x + 4)
(2x - 1) (3x + 4)
These are the factors
Answer: 430 rounded so ur answer is 400
Step-by-step explanation:
you do 86 times 5 and you get 430 the you round it to the nearest hundred and you get 400 as ur answer
Answer:
44+54= 98
98-13=85
Step-by-step explanation:
