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pychu [463]
3 years ago
9

How to write Edith must read for a minimum of 20 minutes

Mathematics
1 answer:
Zolol [24]3 years ago
7 0
X ≥ 20
x = total number of minutes read
20 = minimum amount of minutes read
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In Amy's garden the ratio of herbs to plants is 5:2. If there are 40 herb plants, how many vegetable plants are in her garden?
GREYUIT [131]
There are 16 vegetable plants because 40/5 is 8 and 2 times 8 is 16. 5:2=40:16
4 0
3 years ago
Orianna had 10 tiles to arrange in a rectangular design. She drew a model of the rectangles she could make with the 10 tiles. As
tensa zangetsu [6.8K]
Answer:

There are four possible rectangles with 10 tiles.

Step-by-step explanation:
The question for this problem is: How many different rectangles could she make with the 10 tiles?

All the dimensions possible are all products that give 10 as a result. So, all possible rectangles would be:
2 width x 5 length = 10
5 width x 2 length = 10
1 width x 10 length = 10
10 width x 1 length = 10
4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge
BabaBlast [244]

\underline{\bf{Given \:equation:-}}

\\ \sf{:}\dashrightarrow ax^2+by+c=0

\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.

\sf We\:know,

\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}

\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}

\underline{\large{\bf Identities\:used:-}}

\boxed{\sf (a+b)^2=a^2+2ab+b^2}

\boxed{\sf (√a)^2=a}

\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}

\boxed{\sf \sqrt{\sqrt{a}}=a}

\underline{\bf Final\: Solution:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}

\bull\sf Apply\: Squares

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}

\bull\sf Put\:values

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}

\bull\sf Simplify

\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}

\underline{\bf More\: simplification:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}

\underline{\Large{\bf Simplified\: Answer:-}}

\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}

5 0
2 years ago
Read 2 more answers
PLEASE LOOK at the photo and help me on these 2 questions :(!!!!!
Tems11 [23]

Answer:

1) f(g(2)) = 24

2) f(g(-1)) = -4

Step-by-step explanation:

1) GIven f(x) = x²+2x and g(x) = 2x

f(g(x)) = f(2x)

f(2x) = (2x)² + 2(2x)

f(2x) = 4x² + 4x

f(g(x)) = 4x² + 4x

f(g(2)) = 4(2)² + 4(2)

f(g(2)) = 16+8

f(g(2)) = 24

2) f(x) = x+1 and g(x) = 5x

f(g(x)) = f(5x)

f(5x)= 5x + 1

f(g(x)) = 5x + 1

f(g(-1)) = 5(-1) + 1

f(g(-1)) = -5+1

f(g(-1)) = -4

8 0
3 years ago
How many whole numbers are there up to 100, including 100?​
vladimir2022 [97]

Answer:

100

Step-by-step explanation:

because... LOGIC

5 0
3 years ago
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