Question

A dielectric material, such as Teflon®, is placed between the plates of a parallel-plate capacitor without altering the structure of the capacitor. The charge on the capacitor is held fixed. How is the voltage across the plates of the capacitor affected?

Answer 1

Answer:

1/ K times

Explanation:

The capacitance of a parallel plate capacitor is given by

$C = \frac{\varepsilon _{0}A}{d}$

Where, A be the area of plates and d be the distance between the plates.

When a dielectric is inserted between the plates, the new capacitance is

$C' = \frac{k\varepsilon _{0}A}{d}=kC$

The charge remains same.

As we know that

q = C V

The capacitance becomes KC so, to keep the charge remains same the potential difference should be 1 / K times.

V' = V / K