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3 years ago

What is less dense water or oil steel or water helium or air or oil or water

Physics

2 answers:

Andre45 [30]3 years ago

5 0

Oil is less dense than water.

Water is less dense than steel.

Helium is less dense than air.

Leni [432]3 years ago

4 0

Answer:

air because their is nothing contained within the air other than all the solutions that you have listed

Explanation:

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A glass windowpane in a home is 0.62 cm thick and has dimen- sions of 1.0 m 3 2.0 m. On a certain day, the indoor temper- ature

DIA [1.3K]

Answer:

Explanation:

Thermal conductivity of glass pane = .8 W / m K

For conduction of heat , the formula is as follows

Q = $\frac{kA(T_1 - T_2 )t}{d }$ ; Q is heat conducted in time t by a medium of thickness d , area of cross section A and ( T₁ - T₂ ) is the temperature difference .

Putting the values in the equation

Q = $\frac{.8 \times32\times(25 - 0 )\times1}{.0062 }$

= 103225.8 W

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energy lost in one day

= 103225.8 x 24 x 60 x 60

= .89187 x 10¹⁰ J .

6 0

3 years ago

How much kinetic energy does a proton gain if it is accelerated, with no friction, through a potential difference of 1.00 V? The

ra1l [238]

Answer:

If energy is conserved, then the sum of the potential energy and the kinetic energy is a constant.

Assuming the proton starts from rest, so it's kineitc energy is zero, but it has a potential energy, PE equal to:

PE = qV

where q =1.6 x 10^-19 C

and V = 1.00 V

Assuming the proton no longer experiences the potential energy and it is all converted to kinetic energy then:

PE* = 0,

KE* = 1/(2mv^2)

Now since

PE + KE = Total energy =PE* + KE*

Therefore,

qV + 0 = 0 + 1/2mv^2

KE = qV = 1.6 10^-19 J

4 0

3 years ago

The ball of a ballpoint pen is 0.5 mm in diameter and has an ASTM grain size of 12. How many grainsare there in the ball

Alina [70]

Answer:

the number of grains in the ball is 274,848

Explanation:

Given that;

diameter = 0.5 mm

so radius r = 0.25 mm

first we determine the volume of the ball using the following equation;

V = 4/3×πr³

we substitute

V = 4/3×π(0.25)³

V = 0.06544 mm³

Now form table 1.1 "Grain sizes" a metal with grain size number of 12 has about 4,200,000 grains/mm³

so;

Number of grains N = 0.06544 × 4,200,000

N = 274,848 grains

Therefore, the number of grains in the ball is 274,848

5 0

2 years ago

The magnitude of the gravitational field strength near Earth's surface is represented by

Zanzabum

Answer:

The magnitude of the gravitational field strength near Earth's surface is represented by approximately $9.82\,\frac{m}{s^{2}}$ .

Explanation:

Let be M and m the masses of the planet and a person standing on the surface of the planet, so that M >> m. The attraction force between the planet and the person is represented by the Newton's Law of Gravitation:

$F = G\cdot \frac{M\cdot m}{r^{2}}$

Where:

$M$ - Mass of the planet Earth, measured in kilograms.

$m$ - Mass of the person, measured in kilograms.

$r$ - Radius of the Earth, measured in meters.

$G$ - Gravitational constant, measured in $\frac{m^{3}}{kg\cdot s^{2}}$ .

But also, the magnitude of the gravitational field is given by the definition of weight, that is:

$F = m \cdot g$

Where:

$m$ - Mass of the person, measured in kilograms.

$g$ - Gravity constant, measured in meters per square second.

After comparing this expression with the first one, the following equivalence is found:

$g = \frac{G\cdot M}{r^{2}}$

Given that $G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}$ , $M = 5.972 \times 10^{24}\,kg$ and $r = 6.371 \times 10^{6}\,m$ , the magnitude of the gravitational field near Earth's surface is: