The following balanced equation shows the decomposition of water (H2O). According to the equation, how many oxygen atoms are in
2 answers:
Answer : The number of oxygen atoms present on reactant side are, 4
Explanation :
Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.
Decomposition reaction : It is defined as the reaction in which the larger molecule decomposes to give two or more smaller molecules as a product.
The given balanced chemical reaction is,
From the balanced chemical reaction we conclude that, there 4 atoms of hydrogen and 2 atoms of oxygen present on both reactant side and product side.
Hence, the number of oxygen atoms present on reactant side are, 4
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Water decomposes when electrolyzed to produce hydrogen and oxygen gas. If 2.5 grams of water were decomposed 1.04 grams of oxygen will be formed.
BCA table:
2O ⇒
+
B 0.13 0 + 0
C -0.13 0.065 + 0.065
A 0 0.065
Explanation:
Balanced equation for water decomposition into hydrogen and oxygen gases
2O ⇒
+
B 0.13 0 + 0
C -0.13 0.065 + 0.065
A 0 0.065
Number of moles of water =
mass = 2.5 grams
atomic mass= 18 grams
number of moles can be known by putting the values in the formula,
n =
= 0.13 moles
2 moles of water gives one mole of oxygen on decomposition
so, 0.13 moles of water will give x moles of oxygen on decompsition
=
x = 0.065 moles of oxygen will be formed.
moles to gram will be calculated as
mass =number of moles x atomic mass
= 0.065 x 16
= 1.04 grams of oxygen.
Explanation:
A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.
The given reaction is
Now, we balance the mass on both reactant and product side as follows.
235 + 1 =
236 = 234 + x
x = 236 -234
= 2
So, now we balance the charge on both reactant and product side as follows.
92 + 0 =
92 = 96 - y
y = 4
Thus, we can conclude that there are 2 neutrons and 4 beta-particles are produced in the given reaction.
Therefore, reaction equation will be as follows.