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Tju [1.3M]
3 years ago
9

A mass of 3.6g of magnesium reacts in excess chlorine to form a chloride, if the mass of the chloride is 14.25g, find the formul

a of the chloride formed​
Chemistry
1 answer:
mario62 [17]3 years ago
6 0

Answer:

MgCl2

Explanation:

From the question given,

Mass of Mg = 3.6g

Mass of the chloride = 14.25g

Note: the chloride contains Mg and Cl

Mass of Cl = Mass of chloride — Mass of Mg

Mass of Cl = 14.25 — 3.6 = 10.65g

Now we can easily obtain the formula of chloride as follow:

Mg = 3.6g

Cl = 10.65g

Divide by their molar mass

Mg = 3.6/24 = 0.15

Cl = 10.65/35.5 = 0.3

Divide by the smallest

Mg = 0.15/0.15 = 1

Cl = 0.3/0.15 = 2

Therefore, the formula of chloride is MgCl2

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Explanation:

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A student balanced the chemical equation Mg + O2 →MgO by writing Mg + O2 → MgO2. Was the equation balanced correctly? Explain yo
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Explanation:

Charges on both magnesium and oxygen is 2. Though opposite in sign, they have equal charges so, both of them will be cancelled by each other.

As a result, formula of magnesium oxide is MgO and not MgO_{2}.

The student write the equation as Mg + O_2 \rightarrow MgO_2, it is not correct.

Therefore, given equation will be balanced as follows.

          2Mg + O_{2} \rightarrow 2MgO

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7 0
3 years ago
Please help I don’t have a lot of time left
Harrizon [31]

Answer:

So sorry if I was wrong but I think it's B. Because from the source states,

https://socratic.org/questions/which-group-on-the-periodic-table-is-the-least-reactive-why

"The least reactive elements are those who have a full outermost valence shell ie they have 8 electrons in the outer shell so elements such as helium, neon, radon or the transition elements."

5 0
2 years ago
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A rotameter calibration curve (flow rate versus float position) obtained using a liquid is mistakenly used to measure a gas flow
Veronika [31]

Answer:

I would expect the gas rate determined in this manner to be too low

Explanation:

A Rotameter can be designed to respond to the sensitivity of density, velocity, to measure the flow rate of liquid or gas enclosed in a tube. Liquids are denser than gas, and since the gas rate to be determined needed to respond to the velocity head alone of the rotameter so as to bring the forces in the tube equilibrium. Knowing if there is no flow, then the float would remain at the bottom, so gas has to flow at a higher rate compared to the liquid so the float would be in a similar position making it easier to measure the flowrate. This leaves the gas rate to be determined too low.

5 0
2 years ago
The value of Ka for nitrous acid (HNO2) at 25 ∘C is 4.5×10−4 .a. Write the chemical equation for the equilibrium that correspond
kvv77 [185]

Answers and Explanation:

a)- The chemical equation for the corresponden equilibrium of Ka1 is:

2. HNO2(aq)⇌H+(aq)+NO−2

Because Ka1 correspond to a dissociation equilibrium. Nitrous acid (HNO₂) losses a proton (H⁺) and gives the monovalent anion NO₂⁻.

b)- The relation between Ka and the free energy change (ΔG) is given by the following equation:

ΔG= ΔGº + RT ln Q

Where T is the temperature (T= 25ºc= 298 K) and R is the gases constant (8.314 J/K.mol)

At the equilibrium: ΔG=0 and Q= Ka. So, we can calculate ΔGº by introducing the value of Ka:

⇒ 0 = ΔGº + RT ln Ka

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  ΔGº= 19092.8 J/mol

c)- According to the previous demonstation, at equilibrium ΔG= 0.

d)- In a non-equilibrium condition, we have Q which is calculated with the concentrations of products and reactions in a non equilibrium state:

ΔG= ΔGº + RT ln Q

Q= ((H⁺) (NO₂⁻))/(HNO₂)

Q= ( (5.9 10⁻² M) x (6.7 10⁻⁴ M) ) / (0.21 M)

Q= 1.88 10⁻⁴

We know that   ΔGº= 19092.8 J/mol, so:

ΔG= ΔGº + RT ln Q

ΔG= 19092.8 J/mol + (8.314 J/K.mol x 298 K x ln (1.88 10⁻⁴)

ΔG= -2162.4 J/mol

Notice that ΔG<0, so the process is spontaneous in that direction.

6 0
3 years ago
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