Stoichiometry <span>of the reaction:
</span><span>2 KClO</span>₃<span> = 2 KCl + 3 O</span>₂
↓ ↓
2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?
KClO₃ = 2 * 3 / 2
KClO₃ = 6 / 2
= 3 moles de KClO₃
hope this helps!
2 SO₃ --> 2 SO₂ + O₂
I 12 0 0
C -2x +2x +x
---------------------------------------------
E 12-2x 2x x
Since the moles of SO₂ at equilibrium is 3 mol, 2x = 3. Then, x = 1.5 mol. So, the amounts at equilibrium is:
SO₃: 12 - 2(1.5) = 9
SO₂: 2(1.5) = 3
O₂: 1.5
The formula for K basing on the stoichiometric reaction is:
K = [SO₂]²[O₂]/[SO₃]²
where the unit used is conc in mol/L.
K = [3 mol/3 L]²[1.5 mol/3 L]/[9 mol/3 L]²
<em>K = 0.0556</em>
You always adjust numbers and it will be before the element
so you Neva add or change a subscript
Answer : The rate law for the overall reaction is, ![Rate=k[NO]^2[H_2]](https://tex.z-dn.net/?f=Rate%3Dk%5BNO%5D%5E2%5BH_2%5D)
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
As we are given the mechanism for the reaction :
Step 1 :
(slow)
Step 2 :
(fast)
Overall reaction : 
The rate law expression for overall reaction should be in terms of
.
As we know that the slow step is the rate determining step. So,
The slow step reaction is,

The expression of rate law for this reaction will be,
![Rate=k[NO]^2[H_2]](https://tex.z-dn.net/?f=Rate%3Dk%5BNO%5D%5E2%5BH_2%5D)
Hence, the rate law for the overall reaction is, ![Rate=k[NO]^2[H_2]](https://tex.z-dn.net/?f=Rate%3Dk%5BNO%5D%5E2%5BH_2%5D)