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MrRa [10]
3 years ago
8

It is difficult to measure the volume of a gas because: Gases have no volume. Gases are not soluble in liquids. The volume of a

gas depends on the container. All of the above.
Chemistry
2 answers:
Arada [10]3 years ago
8 0

Answer: The volume of a gas depends on the container.

Explanation:

In the gaseous state of matter, the molecules are present in irregular pattern. The molecules are not closely packed and they can move freely from one place to another and have high kinetic energy.

The molecules have weakest intermolecular forces of attraction and thus do not possess any definite shape and no definite volume.

They occupy the whole volume of the container due to their free movement.

For example : Helium gas

NeTakaya3 years ago
7 0
The volume of the gas depends on the container
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.400 moles of CO2 gas are confined in a 5.00-liter container at 25 °C. Calculate the pressure exerted in atmospheres and mm Hg.
solong [7]

The pressure exerted by 0.400 moles of carbon dioxide in a 5.00 Liter container at 25 °C would be 1.9563 atm or  1486.788 mm Hg.

<h3>The ideal gas law</h3>

According to the ideal gas law, the product of the pressure and volume of a gas is a constant.

This can be mathematically expressed as:

pv = nRT

Where:

p = pressure of the gas

v = volume

n = number of moles

R = Rydberg constant (0.08206 L•atm•mol-1K)

T = temperature.

In this case:

p is what we are looking for.

v = 5.00 L

n = 0.400 moles

T = 25 + 273

 = 298 K

Now, let's make p the subject of the formula of the equation.

p = nRT/v

  = 0.400 x 0.08206 x 298/5

  = 1.9563 atm

Recall that: 1 atm = 760 mm Hg

Thus:

1.9563 atm = 1.9563 x 760 mm Hg

                   = 1486.788 mm Hg

In other words, the pressure exerted by the gas in atm is 1.9563 atm and in mm HG is 1486.788 mm Hg.

More on the ideal gas law can be found here: brainly.com/question/28257995

#SPJ1

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Answer= C) CN contains a covalent bond.

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Why is U-235 the most common nuclear fuel instead of the more abundant U-238? State a clear topic sentence and support it with e
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<h3><u>Answer and explanation</u>;</h3>
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