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2 years ago

Find the Surface Area of the cone.

Mathematics

1 answer:

Snezhnost [94]2 years ago

7 0

Answer:

$\sf \huge{\boxed{\sf area = 653.1 cm^2}}$

Explanation:

$\sf \boxed{\sf area \ of \ cone=\pi r^2 +\pi rl }$

Given:

radius: 8 m

slant height: 18 m

using this formula:

$\hookrightarrow \sf \pi r^2 + \pi rl$

$\hookrightarrow \sf (3.14)(8)^2 +(3.14)(8)(18)$

$\hookrightarrow \sf 653.1 cm^2$

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Please help me with this please actually help me please and thank you

Westkost [7]

Answer:

C. (x, y) → (x, -y)

Step-by-step explanation:

The algebraic representation that correctly describes a reflection over the x-axis is (x, y) → (x, -y)

Here's an example to show understanding

Plot A is (4,6) and the reflection over the x-axis would be (4,-6)

8 0

2 years ago

if a cylinder with height 9 inches and radius r is filled with water, it can fill a certain pitcher. how many of these pitchers

dalvyx [7]

Answer:

4 pitchers

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

$V=\pi r^{2}h$

step 1

Find the volume of the cylinder with height 9 inches and radius r

substitute the given values

$V_1=\pi r^{2}(9)$

$V_1=9\pi r^{2}\ in^3$

step 2

Find the volume of the cylinder with height 9 inches and radius 2r

substitute the given values

$V_2=\pi (2r)^{2}(9)$

$V_2=36\pi r^{2}\ in^3$

step 3

we know that

The volume of the cylinder 1 can fill a certain pitcher,

The volume of the pitcher is the same that the volume of cylinder 1

therefore

the number of pitchers that can be filled by the second cylinder is equal to divide the volume of the second cylinder by the volume of the first cylinder

$\frac{36\pi r^{2}}{9\pi r^{2}}=4\ pitchers$

3 0

3 years ago

Convert to factored form y = x² + 6x

steposvetlana [31]

Convert to factored form is:

$y = x(x + 6)$

Solution:

Given that,

$y = x^2 + 6x$

We have to convert to factored form

Factored form means writing terms in multiplication. i.e as a product

From given,

$y = x^2 + 6x$

Factor out x from above given expression

$y = x(x + 6)$

Here, the given equation is written as product of "x" and (x + 6)

Thus the factored form is found

8 0

3 years ago

-2 1/3 divided by -3/5

Aleonysh [2.5K]

Answer:

나는 대답이 글꼴 알고 있다고 생각한다.나는 대답이 글꼴 알고 있다고 생각한다.

7 0

2 years ago

Hello again! This is another Calculus question to be explained.

podryga [215]

Answer:

See explanation.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions

Function Notation

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

We are given the following and are trying to find the second derivative at x = 2:

$\displaystyle f(2) = 2$

$\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}$

We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:

$\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}$

When we differentiate this, we must follow the Chain Rule: $\displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big]$

Use the Basic Power Rule:

$\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} (2x + 6yy')$

We know that y' is the notation for the 1st derivative. Substitute in the 1st derivative equation:

$\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 6y(6\sqrt{x^2 + 3y^2}) \big]$

Simplifying it, we have:

$\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]$

We can rewrite the 2nd derivative using exponential rules:

$\displaystyle \frac{d^2y}{dx^2} = \frac{3\big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]}{\sqrt{x^2 + 3y^2}}$

To evaluate the 2nd derivative at x = 2, simply substitute in x = 2 and the value f(2) = 2 into it:

$\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = \frac{3\big[ 2(2) + 36(2)\sqrt{2^2 + 3(2)^2} \big]}{\sqrt{2^2 + 3(2)^2}}$

When we evaluate this using order of operations, we should obtain our answer:

$\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = 219$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0

2 years ago