n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
# of terms: 2
inConstant(s): might be wrong but i think its 5
Coefficient(s): might be y itself but i dont know
Highest degree: 5
I did what I could but this number is not factorable with rational numbers
Considering the Central Limit Theorem, we have that:
a) The probability cannot be calculated, as the underlying distribution is not normal and the sample size is less than 30.
b) The probability can be calculated, as the sample size is greater than 30.
<h3>What does the Central Limit Theorem state?</h3>
It states that the sampling distribution of sample means of size n is approximately normal has standard deviation
, as long as the underlying distribution is normal or the sample size is greater than 30.
In this problem, the underlying distribution is skewed right, that is, not normal, hence:
- For item a, the probability cannot be calculated, as the underlying distribution is not normal and the sample size is less than 30.
- For item b, the probability can be calculated, as the sample size is greater than 30.
More can be learned about the Central Limit Theorem at brainly.com/question/16695444
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I would say b the reason is because -2 is on the x and -6 in on the y so it would be left then down.