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3 years ago

What is 4.12 rounded to nearest tenth?

2 answers:

8 0

when rounding to the nearest tenth, we have to see the digit in the hundredths place, if the digit is equal to or greater than 5, then we add 0.1, if the digit is less than 5 then there's no change to the digit in the tenths place

tenths place is the first number to the right of the decimal point

hundredths place is the number to the right of the tenths place

in the given number 4.12

digit in the hundredths place is 2, its less than 5 so there's no change to the digit in the tenths place

so 4.12 rounded to the nearest tenth is - 4.1

Dvinal [7]3 years ago

5 0

You round to the first decimal place so you get 4.1

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Use slopes and y-intercepts to determine if the lines y=−2/3x+2 and −3x+2y=−4 are parallel.

EleoNora [17]

Answer:

the answer is no

Step-by-step explanation:

y = -2/3x+2

2y = 3y-4

y = 3/2y-2

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2 years ago

A karate studio charges $35 for the first course and $22. 50 for each course after that, even if the student leaves the course e

VashaNatasha [74]

The Cena can take 7 courses

We have given that the karate charges $35 for the first course and $22.50 for each course after that. Our total is $170.

<h3>What is the condition we can write here?</h3>

$22.50x + 35 = 170$

for solving this linear equation

First, subtract 35 from both sides.

$22.50x = 135$

isolate x so divide both sides by 22.50.

$x=\frac{135}{22.50}$

Therefore we get x = 6

Remember to add the additional class, so x is actually 7.

So,the Cena can take 7 courses.

To learn more about the linear equation visit:

brainly.com/question/1549055

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2 years ago

Determine whether line AB and line CD are parallel, perpendicular, or neither. A( 4, 2), B(-3, 1), C(6, 0), D(-10, 8)

Lapatulllka [165]

Answer:

<h2>neither</h2>

Step-by-step explanation:

If AB an CD are parallel, then their slopes are the same.

If AB and CD are perpendicular, then the product of their slopes is equal -1.

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Calculate the both slope:

$A(4,\ 2),\ B(-3,\ 1)\\\\m_{AB}=\dfrac{1-2}{-3-4}=\dfrac{-1}{-7}=\dfrac{1}{7}\\\\C(6,\ 0),\ D(-10,\ 8)\\\\m_{CD}=\dfrac{8-0}{-10-6}=\dfrac{8}{-16}=-\dfrac{1}{2}\\\\=============================$