All categories

2 years ago

8.09 is greater than 8.090

Mathematics

2 answers:

balandron [24]2 years ago

6 0

Answer:

They are actually equal.

Step-by-step explanation:

8.09 is equal to 8.090

They both have the same tenth(0) and the same hundredth(9).

A simple way to put this is to just add a zero to 8.09.

8.090

hram777 [196]2 years ago

6 0

Answer:

false

Step-by-step explanation:

the only zero that matters is the one before the 9. so, if it was 8.009, ts smaller by one thousandth. if i had 8.09<u>000000000</u>, all the underlined zeros would mean nothing because they arent anything. they are the absence of a value.

You might be interested in

a) A large hotel in Miami has 900 rooms (all rooms are equivalent). During Christmas, the hotel is usually fully booked. However

Olegator [25]

Answer:

14.69% probability that this happens

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

1000 people were given assurance of a room.

This means that $n = 1000$

Let us assume that each customer cancels their reservation with a probability of 0.1.

So 0.9 probability that they still keep their booking, which means that $p = 0.9$

Probability more than 900 still keeps their booking:

$n = 1000, p = 0.9$

$\mu = 0.9, s = \sqrt{\frac{0.9*0.1}{1000}} = 0.0095$

901/1000 = 0.91

So this is 1 subtracted by the pvalue of Z when X = 0.91.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{0.91 - 0.9}{0.0095}$

$Z = 1.05$

$Z = 1.05$ has a pvalue of 0.8531

1 - 0.8531 = 0.1469

14.69% probability that this happens

3 0

2 years ago

Round $18.937 to the nearest cent

inysia [295]

It would be $18.94, because the hundredths place is the penny.

8 0

2 years ago

Read 2 more answers

G(x)=-x^2/4 +7<br> Over which interval does g have a negative average rate of change?

Sholpan [36]

Answer:

x = 49

Step-by-step explanation:

1- Substitute g ( x ) = 0

Reduce

g ( x ) = - x 2/4 + 7

2- Move the variable to the left

0 = - x 1/2 + 7

3- Simplify the equation

x 1/2 = 7

4- Simplify Evaluate

( x 1/2 ) ² = 7²

5- Check the solution

x= 49

6- Simplify

0= - 49 2/4 + 7

7- x = 49 is a solution

0 = 0

4 0

2 years ago

At a recent marathon, spectators lined the street near the starting line to cheer for the runners. The crowd lined up 5 feet dee

masha68 [24]

Answer:

29568 people cheered for the runners at the start of the race

Step-by-step explanation:

From the question, the crowd lined up 5 feet deep on both sides of the street for the first mile.

This lined up crowd could be related to a rectangle that is 1 mile long and 5 feet wide.

First, Convert 1 mile to feet

1 mile = 5280 feet

Hence, the length of the rectangle is 5280 feet and the width is 5 feet.

Now, we will determine how many 5 feet by 5 feet square we can get from the 5280 feet by 5 feet rectangle. To do that, we will divide 5280 feet by 5 feet

5280 feet ÷ 5 feet = 1056

Hence, from the rectangle, we can get 1056 5 feet by 5 feet square.

From the question, you estimate that 14 people can comfortably fit in a square that measures 5 feet by 5 feet,

∴ 14 × 1056 people will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

14 × 1056 = 14784 people

This is the amount of people that will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

Since the crowd lined up on both sides of the street, then

2 × 14784 people will comfortably fit in the crowed lined up 5 feet deep on both sides of the street for the first mile

2 × 14784 = 29568 people

Hence, 29568 people cheered for the runners at the start of the race.

5 0

3 years ago

What is the measure of

charle [14.2K]

Answer:

of what??

Step-by-step explanation:

?..............

4 0

2 years ago

8.09 is greater than 8.090​

8.09 is greater than 8.090