Evaluate the sum of the finite geometric series. 1+2+4+8+...+128

1 answer:

7 0

S = a*((1 - r^(n+1))/(1-r)) S = 1*((1 - 2^(7+1))/(1-2)) S = 1*((1 - 2^8)/(1-2)) S = 1*((1 - 256)/(1-2)) S = 1*((-255)/(-1)) S = 255 So 1+2+4+8+...+128 = 255

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I am assuming that the attached is the complete question and we need to get the information from the table.

From the table we know the below fact:

$1 \; small \; container \; of \; potato \; salad \; Weighs \; \frac{2}{8} \; pounds\\\\1 \; extra \; large \; container \; of \; potato \; salad \; Weighs \; \frac{9}{8} \; pounds$

$Weight \; of \; 6 \; small \; container = 6 \times \frac{2}{8} = \frac{12}{8} \; pounds\\\\Weight \; of \; 2 \; Extra \; large \; container = 2 \times \frac{9}{8} \; = \; \frac{18}{8} \; pounds$

Conclusion:

The difference in weights, in pounds of Kim’s and Seth’s purchases is given below:

$\frac{18}{8} - \frac{12}{8} = \frac{18-12}{8} = \frac{6}{8} \\\\Simplifying \; the \; fraction \; dividing \; by \; 2 \; on \; both \; numerator \; and \; denominator\\\\ \frac{6 \div 2}{8 \div 2} = \frac{3}{4}$