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2 years ago

Evaluate the sum of the finite geometric series. 1+2+4+8+...+128

1 answer:

7 0

S = a*((1 - r^(n+1))/(1-r)) S = 1*((1 - 2^(7+1))/(1-2)) S = 1*((1 - 2^8)/(1-2)) S = 1*((1 - 256)/(1-2)) S = 1*((-255)/(-1)) S = 255 So 1+2+4+8+...+128 = 255

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The equation that corresponds to this diagram is 6 (x+ 1)=24.

Annette [7]

Answer:

x is 3

Step-by-step explanation:

6 (x + 1) = 24

6 (x) + 6(1) = 24

6x + 6 = 24

Subtract 6 on both sides

6x + 6 - 6 = 24 - 6

6x + 0 = 18

6x = 18

x = 18/6

x = 3

7 0

2 years ago

For each situation below, write the equation of the line and explain how you can tell.

sveticcg [70]

Answer:

see below

Step-by-step explanation:

a. Has a slope of 2 and passes through (10,17)

Using the slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = 2x+b

Substitute the point into the equation

17 = 2(10)+b

17 = 20+b

Subtract 20 from each side

17-20 =b

-3 =b

y = 2x-3

b. passes through (1,-4) and (2,-5)

First find the slope

m= (y2-y1)/(x2-x1)

= (-5- -4)/(2-1)

= (-5+4)/(2-1)

= -1/1

= -1

Using the slope intercept form

y = -x+b

Substitute a point into the equation

-4 = -1(1) +b

-4 = -1+b

Add 1 to each side

-3 = b

y = -x+3

6 0

3 years ago

Determine whether the sides given would form an acute, obtuse, or right triangle. 7, 7, 13

Brut [27]

Let a = 7 , b = 7, and c = 13. c is always the biggest number.

Acute Triangle is when $c^2 \ \textless \ a^2 + b^2$

Right Triangle is when $c^2 = a^2 + b^2$

Obtuse Triangle is when $c^2 \ \textgreater \ a^2 + b^2$