Answer:
C (11.3) = 165
P (3,3) = 6
Step-by-step explanation:
We want to select 3 players out of 11 regardless of the order. That is, there is no difference between selecting the players {2,5,7} or {7,2,5}
Then we use the formula of combinations:
There are 165 ways to choose 3 players out of 11.
Now we want to know how many ways you can designate those 3 players as first, second and third. Now if we care about the order of selection. Then we use permutations.
They can be designated in 6 different ways
The answer i came up with is : (4b-7x) (a+2)
Answer:
3
Step-by-step explanation:
double negatives equal positive if it was -9-6 than it will be -3 because the nine is bigger
1. y - y₁ = m(x - x₁)
y - (-7) = 6(x - (-8))
y + 7 = 6(x + 8)
y + 7 = 6(x) + 6(8)
y + 7 = 6x + 48
<u> - 7 - 7</u>
y = 6x + 41
2. <u>y₂ - y₁</u> = <u>-8 - (-3)</u> = <u>-8</u><u> + 3</u> = <u>-5</u> = -1²/₃
x₂ - x₁ -1 - (-4) -1 + 4 3
3. 2x - 3y = 11
<u>3x + 3y = 9</u>
<u>5x</u> = <u>20</u>
5 5
x = 4
2x - 3y = 11
2(4) - 3y = 11
8 - 3y = 11
<u>- 8 - 8</u>
<u>-3y</u> = <u>3</u>
-3 -3
y = -1
(x, y) = (4, -1)
4. 2x - 5y = -7 ⇒ -6x + 15y = 21
5x - 3y = 11 ⇒ <u>-25x + 15y = -55</u>
<u>19x</u> = <u>76</u>
19 19
x = 4
2x - 5y = -7
2(4) - 5y = -7
8 - 5y = -7
<u>- 8 - 8</u>
<u>-5y</u> = <u>-15</u>
-5 -5
y = 3
(x, y) = (4, 3)
5. 4.9 × 10¹¹, 8.9 × 10¹⁸, 1.3 × 10⁸, 6.7 × 10⁸, 2.7 × 10⁸
<u>1.3 × 10³</u>, 2.7 × 10⁸, 6.7 × 10⁸, 4.9 × 10¹¹, <u>8.9 × 10¹⁸</u>
Least Greatest
Answer:
no helping with exAMS allowed~~~!!!!
Step-by-step explanation:
