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4 years ago

If f(x)= 2a|3x – 9| – ax, where a is some constant not equal to zero, find f ′(3).

Mathematics

1 answer:

sineoko [7]4 years ago

8 0

Hmm, it actually doesn't exist because at x=3, that is where the absoluve value turns into 0. the graph has a point at x=3 and there is no slope of a pointy part of a function. I mean the slope is undinfed, it is DNE

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Find the inverse function of<br> y =x-5/6

kirill115 [55]

$f(x) = y = x - \frac{5}{6} \\$

Subtract the sides of the equation plus 5/6

$y + \frac{5}{6} = x \\$

So ;

${f}^{ - 1}(x) = x + \frac{5}{6} \\$

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And we're done.

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3 years ago

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Find the missing side.

Hitman42 [59]

Answer:

24.8

Step-by-step explanation:

sin75 = 24/x

x = 24/sin75 = 24.8466 = 24.8 (nearest tenth)

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3 years ago

Does the set {t, t Int} form a fundamental set of solutions for t^2y" -- ty' +y = 0?

Ivanshal [37]

Answer:

yes

Step-by-step explanation:

We are given that a Cauchy Euler's equation

$t^2y''-ty'+y=0$ where t is not equal to zero

We are given that two solutions of given Cauchy Euler's equation are t,t ln t

We have to find the solutions are independent or dependent.

To find the solutions are independent or dependent we use wronskain

$w(x)=\begin{vmatrix}y_1&y_2\\y'_1&y'_2\end{vmatrix}$

If wrosnkian is not equal to zero then solutions are dependent and if wronskian is zero then the set of solution is independent.

Let $y_1=t,y_2=t ln t$

$y'_1=1,y'_2=lnt+1$

$w(x)=\begin{vmatrix}t&t lnt\\1&lnt+1\end{vmatrix}$

$w(x)=t(lnt+1)-tlnt=tlnt+t-tlnt=t$ where t is not equal to zero.

Hence,the wronskian is not equal to zero .Therefore, the set of solutions is independent.

Hence, the set {t , tln t} form a fundamental set of solutions for given equation.

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4 years ago

Which one the answer?

kifflom [539]

D. Hope this helps ;)

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3 years ago

Lizette is training for a marathon. At 7:00 she left her house and ran until 8:30, then she walked until 11:30. She covered a to

Leokris [45]

<h3>Answer:</h3>

running speed: 8 mph
walking speed: 2 mph

<h3>Step-by-step explanation:</h3>

Let w represent Lizette's walking speed. Then her running speed is w+6. The relationship between speed, time, and distance is ...

distance = speed × time

Lizette ran for 1.5 hours, then walked for 3 hours. Her total distance is ...

(w+6)·1.5 + w·3 = 18

4.5w + 9 = 18 . . . . . simplify

4.5w = 9 . . . . . . . . . subtract 9

w = 2 . . . . . . . . . . . .divide by 4.5

Lizette's walking speed is 2 mph; her running speed is 8 mph.

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3 years ago

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