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andreyandreev [35.5K]
2 years ago
13

What is the equation of a line with a slope of ​ ​ −4−4 ​ ​ and a point ​ (−2,5) ​

Mathematics
1 answer:
Darya [45]2 years ago
7 0
Here, we can formulate the slope-intercept equation from the point and the slope:

Slope = -4/-4 = 1
x1 = -2
y1 = 5

By point-slope form:

(y-y1)  = m (x - x1)
(y-5) = 1(x +2)

y-5 = x +2

Simplifying to slope-intercept form:

y = x + 7

Therefore, the slope-intercept form would be y = x+7

I hope my answer has come to your help. God bless and have a nice day ahead!
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43 points, 86 for brainliest! Answer correct!! Be wise! According to the image attached, whats the answer?
Snezhnost [94]

Answer:

p = 32\:  \: in

a = 49 {in}^{2}

Step-by-step explanation:

perimeter \\  = 8 + 8+8+8 \\  = 32 \:  \: in

area \\   1)3 \times 8 = 24 \\ 2)5 \times 5 = 25 \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 49 {in}^{2}

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0
3 years ago
Read 2 more answers
Your middle school has 900 students one third of the students bring their lunch instead of buying your lunch at school what is t
r-ruslan [8.4K]
1/3 of all students bring lunch
2:3 is the ratio of students who bring their lunch to the number of students who do not
7 0
3 years ago
There were 12 people on jury there were 4 more men than women how many men were there
AlekseyPX

Answer:

8 men.

Step-by-step explanation:

12÷3=4.

4 women, 8 men.

8-4=4.

6 0
3 years ago
Which of the following is a polynomial A.x^2+2 B.(x^8-2)/(x^-2+3) C. 7x^7-2x^-4+3 D.x^x-1
EastWind [94]
<span> A. x²+2   - a  polynomial
B.(x⁸-2)/(x⁻²+3)  rational function
C. 7x⁷-2x⁻⁴+3 (It has negative value of exponent, so it cannot be a polynomial.)
D.x^x-1 (x is an exponent it cannot be a polynomial)</span>
6 0
3 years ago
What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

4 0
2 years ago
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