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3 years ago

5

A city is building a fence around a rectangular playground. If the perimeter of the playground is 90 feet and the length of one

side of the fence is 28 feet, what is the width of the playground?

2 answers:

Montano1993 [528]3 years ago

6 0

90=l+l+w+w
90=28+28+w+w
90=56+2w
34=2w
17=w
The width of the playground is 17.

Elenna [48]3 years ago

6 0

A rectangle has 2 lengths of the same and 2 widths of the same. so your length is 28(56 for both sides) and subtraact it from 90 wich is yoru total perimite you get 34 and now devide by 2 and your widths will be 17 for both. <span />

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2 years ago

A bowl of buttons contains 10 MAGA [MAKE AMERICA GREAT AGAIN] buttons, 5 GND [GREEN NEW DEAL] buttons and 10 NAW [NEVER A WALL]

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a) Probability of picking Two MAGA buttons without replacement = 0.15

b) Probability of picking a MAGA and GND button in that order = 0.0833

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Step-by-step explanation:

10 MAGA [MAKE AMERICA GREAT AGAIN] buttons, 5 GND [GREEN NEW DEAL] buttons and 10 NAW [NEVER A WALL] buttons.

Total number of buttons = 10 + 5 + 10 = 25

Let probability of picking a MAGA button be P(M) = 10/25 = 0.4

Probability of picking a GND button be P(G) = 5/25 = 0.2

Probability of picking a NAW button be P(N) = 10/25 = 0.4

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b) Probability of picking a MAGA and GND button in that order = (10/25) × (5/24) = 1/12 = 0.0833

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3 years ago

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zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200, 300

Let X be the total refund payment on the seven day cruise.

We can say X = 0, if there is no rain on all 7 days.

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$P(X = 0) =0.2097152$

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$P(X = 100) = _nC_x * P^x * (1 - P)n-x$

$P(X = 100) = _7C_1 * 0.2^1 * (1-0.2)^{7-1$

$P(X = 0) =7 * 0.2* (1-0.2)^{6$

$P(X = 100) =7* 0.2* (0.8)^{6$

$P(X = 100) =0.3670016$

if it rains on any two day ; then X = 200

$P(X = 200) = _nC_x * P^x * (1 - P)n-x$

$P(X = 200) = _7C_2 * 0.2^2 * (1-0.2)^{7-2$

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if it rains on any three day or more than that ; then X = 300

$P(X \ge 300) = 1 - P(X < 300) \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032$

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple $[Var X] =E [X^2] - (E [X])^2$

where;

$E[X^2] = \sum x^2 \times p \\ \\ E[X^2] = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\ E[X^2] = 0 + 3670.016 + 11010.048+ 13322.88 \\ \\ E[X^2] =28002.944$

$(E [X]) = \sum x * p\\ \\ (E [X]) = 0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55$

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

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3 years ago

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OleMash [197]

Answer:

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Step-by-step explanation:

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2 years ago

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