Answer:
Correct option: (a) 0.1452
Step-by-step explanation:
The new test designed for detecting TB is being analysed.
Denote the events as follows:
<em>D</em> = a person has the disease
<em>X</em> = the test is positive.
The information provided is:
![P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99](https://tex.z-dn.net/?f=P%28D%29%3D0.88%5C%5CP%28X%7CD%29%3D0.97%5C%5CP%28X%5E%7Bc%7D%7CD%5E%7Bc%7D%29%3D0.99)
Compute the probability that a person does not have the disease as follows:
![P(D^{c})=1-P(D)=1-0.88=0.12](https://tex.z-dn.net/?f=P%28D%5E%7Bc%7D%29%3D1-P%28D%29%3D1-0.88%3D0.12)
The probability of a person not having the disease is 0.12.
Compute the probability that a randomly selected person is tested negative but does have the disease as follows:
![P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%29%3DP%28X%5E%7Bc%7D%7CD%29P%28D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%20P%28D%29%5C%5C%3D%5B1-0.97%5D%5Ctimes%200.88%5C%5C%3D0.03%5Ctimes%200.88%5C%5C%3D0.0264)
Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:
![P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%5E%7Bc%7D%29%3DP%28X%5E%7Bc%7D%7CD%5E%7Bc%7D%29P%28D%5E%7Bc%7D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%7B1-%20P%28D%29%5D%5C%5C%3D0.99%5Ctimes%200.12%5C%5C%3D0.1188)
Compute the probability that a randomly selected person is tested negative as follows:
![P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%29%3DP%28X%5E%7Bc%7D%5Ccap%20D%29%2BP%28X%5E%7Bc%7D%5Ccap%20D%5E%7Bc%7D%29)
![=0.0264+0.1188\\=0.1452](https://tex.z-dn.net/?f=%3D0.0264%2B0.1188%5C%5C%3D0.1452)
Thus, the probability of the test indicating that the person does not have the disease is 0.1452.
Step-by-step explanation:
DA=13.................
Answer:
Step-by-step explanation:
6 times 4 is 24 so the answer is 24
To represent the number of cans in each shelf you will divide the total number of cans by the number of shelves.
This is represented as
t/4 = n.
He used 40 pounds of the candy worth $1.25 and 30 pounds of the candy worth $1.6.