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Darina [25.2K]
3 years ago
15

Write a net ionic equation to show why solid lithium hydroxide, lioh (s), forms a basic solution when it dissolves in water.

Chemistry
1 answer:
Doss [256]3 years ago
5 0
<span>Solid lithium oxide, the basic anhydride of lithium hydroxide reacts with water to make lithium ions and hydroxide ions. Li2O(s) + H2O(l) --> 2LiOH(aq) ...... molecular equation Li2O(s) + H2O(l) --> 2Li+ + 2OH- ..... ionic equation, and net ionic equation BUT!!!!! The decomposition of potassium chlorate into KCl and O2 gas does not take place in aqueous solution. The equation should be. 2KClO3(s) --> 2KCl(s) + 3O2(g) No ionic equation. There is nothing in solution. This reaction does not occur in aqueous solution. 2Na(s) + I2(g) --> 2NaI(s) No ionic equation. There is nothing in solution. Clearly, to have an ionic equation there must be ions, and to have ions the salts have to be dissolved in water.</span>
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How much of a 400g sample remains after 4 years if a radioactive isotope has a half-life of 2 years?
timama [110]

Answer:

100 g

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 400 g

Time (t) = 4 years

Half-life (t½) = 2 years

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Time (t) = 4 years

Half-life (t½) = 2 years

Number of half-lives (n) =?

n = t / t½

n = 4 / 2

n = 2

Thus, 2 half-lives has elapsed.

Finally, we shall determine the amount remaining of the radioactive isotope. This can be obtained as follow:

Original amount (N₀) = 400 g

Number of half-lives (n) = 2

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2² × 400

N = 1/4 × 400

N = 0.25 × 400

N = 100 g

Thus, the amount of the radioactive isotope remaing is the 100 g.

3 0
3 years ago
Write the definition of a compound and give two examples
QveST [7]

Answer:

a thing that is composed of two or more separate elements ex. Acid and Water

3 0
3 years ago
If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical form
Mumz [18]

he required empirical formula based on the data provided is Na2CO3.H2O.

<h3>What is empirical formula?</h3>

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : brainly.com/question/11588623

3 0
2 years ago
jenny dissolves as much salt as she can in 100mL of room temperature water. she learned in class that less salt will dissolve in
Slav-nsk [51]

Answer:

if ice is added more salt can be dissolved ...........

5 0
3 years ago
Read 2 more answers
Based on the activity series, which metals could X represent in the reaction below? (Note: The equation is not balanced.)
Nikitich [7]
Answer is: A) Sr (strontium).
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3 years ago
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