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4 years ago

Write a net ionic equation to show why solid lithium hydroxide, lioh (s), forms a basic solution when it dissolves in water.

1 answer:

5 0

<span>Solid lithium oxide, the basic anhydride of lithium hydroxide reacts with water to make lithium ions and hydroxide ions. Li2O(s) + H2O(l) --> 2LiOH(aq) ...... molecular equation Li2O(s) + H2O(l) --> 2Li+ + 2OH- ..... ionic equation, and net ionic equation BUT!!!!! The decomposition of potassium chlorate into KCl and O2 gas does not take place in aqueous solution. The equation should be. 2KClO3(s) --> 2KCl(s) + 3O2(g) No ionic equation. There is nothing in solution. This reaction does not occur in aqueous solution. 2Na(s) + I2(g) --> 2NaI(s) No ionic equation. There is nothing in solution. Clearly, to have an ionic equation there must be ions, and to have ions the salts have to be dissolved in water.</span>

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Students working in lab accidentally spilled 17 l of 3.0 m h2so4 solution. they find a large container of acid neutralizer that

bogdanovich [222]

Answer is: 8568.71 of baking soda.

Balanced chemical reaction: H₂SO₄ + 2NaHCO₃ → Na₂SO₄ + 2CO₂ + 2H₂O.

V(H₂SO₄) = 17 L; volume of the sulfuric acid.

c(H₂SO₄) = 3.0 M, molarity of sulfuric acid.

n(H₂SO₄) = V(H₂SO₄) · c(H₂SO₄).

n(H₂SO₄) = 17 L · 3 mol/L.

n(H₂SO₄) = 51 mol; amount of sulfuric acid.

From balanced chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 :2.

n(NaHCO₃) = 2 · 51 mol.

n(NaHCO₃) = 102 mol, amount of baking soda.

m(NaHCO₃) = n(NaHCO₃) · M(NaHCO₃).

m(NaHCO₃) = 102 mol · 84.007 g/mol.

m(NaHCO₃) = 8568.714 g; mass of baking soda.

4 0

3 years ago

Which one of these is not an example of intercellular communication?

Mashcka [7]

the answer is B. ribosomes make protien

7 0

3 years ago

All of the following increase from left to right across the second period of the periodic table (Na - Ar) EXCEPT

DerKrebs [107]

Answer: effective nuclear charge

Explanation: This is because electrons are added to tell same shell at about the same distance from the nucleus

4 0

3 years ago

If 842 grams of sodium hydroxide reacts with 750.0 grams of aluminum, how many grams of aluminum hydroxide should theoretically

Phantasy [73]

548.55 grams of aluminum hydroxide should theoretically form.

Explanation:

Balanced equation for the reaction:

3 NaOH + Al ⇒ Al(OH)3 +3 Na

DATA GIVEN:

mass of NaOH = 842 grams, atomic mass =39.9 grams/mole

mass of Al = 750 grams, atomic mass = 26.9 grams/mole

aluminum hydroxide theoretical yield = ?

Moles of NaOH reacted

number of moles = $\frac{mass}{atomic mass of 1 mole}$

putting the values in the equation

NaOH = $\frac{842}{39.9}$

= 21.1 MOLES OF NaOH

Al = $\frac{750}{26.9}$

= 27.8 moles

from the equation

from 3 moles of NaOH 1 mole of Al(OH)3 is produced

21.1 moles of NaOH will react to give x moles of Al(OH)3

$\frac{1}{3}$ = $\frac{x}{21.1}$

7.03 moles of Al(OH)3 is formed.

and

1 mole of Al(OH)3 is formed from 1 mole of Al in the reaction

so, 27.8 Moles will react to give give 27.8 moles of Al(OH)3 limiting reagent of the given reaction is NaOH

mass of Al(OH)3 =7.03 x 78 (atomic mass of Al(OH)3)

= 548.55 grams

theoretical yield from the given data is 548.55 grams

3 0

3 years ago

Boron has an atomic mass of 10.8 amu. It is known that naturally occurring boron is composed of two isotopes, boron-10 and boron

ANEK [815]

B-10 = 19.9%
B-11 = 80.1%

Abundance of B10 = x
Abundance of B11= y
You know x+y = 1 because there are only the 2 isotopes.
Y= 1-x

10.01294x + 11.00931 (1-x) = 10.811
10.01294x + 11.00931 - 11.00931x = 10.811 - 0.99016x = -0.198
X = 0.200

Check:
10.01294(0.2) + 11.00931 (0.8) = 10.81

20% B10. 80% B11

8 0

3 years ago

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