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4 years ago

Write a net ionic equation to show why solid lithium hydroxide, lioh (s), forms a basic solution when it dissolves in water.

1 answer:

5 0

Solid lithium oxide, the basic anhydride of lithium hydroxide reacts with water to make lithium ions and hydroxide ions. Li2O(s) + H2O(l) --> 2LiOH(aq) ...... molecular equation Li2O(s) + H2O(l) --> 2Li+ + 2OH- ..... ionic equation, and net ionic equation BUT!!!!! The decomposition of potassium chlorate into KCl and O2 gas does not take place in aqueous solution. The equation should be. 2KClO3(s) --> 2KCl(s) + 3O2(g) No ionic equation. There is nothing in solution. This reaction does not occur in aqueous solution. 2Na(s) + I2(g) --> 2NaI(s) No ionic equation. There is nothing in solution. Clearly, to have an ionic equation there must be ions, and to have ions the salts have to be dissolved in water.

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Read 2 more answers

What is the volume of 0.640 grams of Oz gas at Standard Temperature and Pressure (STP)?

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Answer: The volume of 0.640 grams of $O_{2}$ gas at Standard Temperature and Pressure (STP) is 0.449 L.

Explanation:

Given: Mass of $O_{2}$ gas = 0.640 g

Pressure = 1.0 atm

Temperature = 273 K

As number of moles is the mass of substance divided by its molar mass.

So, moles of $O_{2}$ (molar mass = 32.0 g/mol) is as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{0.640 g}{32.0 g/mol}\\= 0.02 mol$

Now, ideal gas equation is used to calculate the volume as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

$PV = nRT\\1.0 atm \times V = 0.02 mol \times 0.0821 L atm/mol K \times 273 K\\V = 0.449 L$

Thus, we can conclude that the volume of 0.640 grams of $O_{2}$ gas at Standard Temperature and Pressure (STP) is 0.449 L.

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