There are four major components found in wood, and these
are:
cellulose
lignin
starch
protein
Among the four, I believe that cellulose and lignin are
the most difficult to degrade because they contain large amount of cross-linked
heavy hydrocarbons.
Answer:
cellulose
lignin
According to this formula when:
ΔG = ΔH - TΔS = 0
∴ ΔS = ΔH/T
∴ ΔS = n*ΔHVap / Tvap
- when n is the number of moles = mass/molar mass
when the mass = 24.1 g
and the molar mass = 187.3764 g/mol
by substitution:
∴ n = 24.1 / 187.3764g/mol
= 0.129 moles
and ΔHvap is the molar enthalpy of vaporization is 27.49 kJ/mol
and Tvap is the temperature in Kelvin = 47.6 + 273 = 320.6 K
So by substitution, we will get the ΔS the change in entropy:
∴ΔS = 0.129 mol * 27490 J/mol / 320.6 K
= 11 J/K
moles NaOH = c · V = 0.2753 mmol/mL · 43.44 mL = 11.959032 mmol
moles H2SO4 = 11.959032 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 5.979516 mmol
Hence
[H2SO4]= n/V = 5.979516 mmol / 54.69 mL = 0.1093 M
The answer to this question is [H2SO4] = 0.1093 M
Answer:
Zero (0)
Explanation:
Since Na^+ has a charge of +1 and Cl^- has a charge of —1 in NaCl
Then the net = +1 —1 = 0
