If 842 grams of sodium hydroxide reacts with 750.0 grams of aluminum, how many grams of aluminum hydroxide should theoretically
1 answer:
548.55 grams of aluminum hydroxide should theoretically form.
Explanation:
Balanced equation for the reaction:
3 NaOH + Al ⇒ Al(OH)3 +3 Na
DATA GIVEN:
mass of NaOH = 842 grams, atomic mass =39.9 grams/mole
mass of Al = 750 grams, atomic mass = 26.9 grams/mole
aluminum hydroxide theoretical yield = ?
Moles of NaOH reacted
number of moles =
putting the values in the equation
NaOH =
= 21.1 MOLES OF NaOH
Al =
= 27.8 moles
from the equation
from 3 moles of NaOH 1 mole of Al(OH)3 is produced
21.1 moles of NaOH will react to give x moles of Al(OH)3
=
7.03 moles of Al(OH)3 is formed.
and
1 mole of Al(OH)3 is formed from 1 mole of Al in the reaction
so, 27.8 Moles will react to give give 27.8 moles of Al(OH)3 limiting reagent of the given reaction is NaOH
mass of Al(OH)3 =7.03 x 78 (atomic mass of Al(OH)3)
= 548.55 grams
theoretical yield from the given data is 548.55 grams
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<h2>1.16 moles</h2>Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>1.16 moles</h3>Hope this helps you
The given reaction is,
In this reaction, the positive and negative ions of both the reactants rearrange resulting in the formation of new compounds. Such a reaction is referred to as the double replacement or the double displacement reaction. These type of reactions usually take place in aqueous medium and one of the products is a precipitate.
Double displacement reactions are of three types, precipitation reaction, neutralization reaction and reaction involving the formation of a gas. The given reaction is a precipitation reaction as one of the products is a solid.