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3 years ago

206,371,39 expanded form

2 answers:

7 0

200,000,000 + 6,000,000 + 300,000 + 70,000 + 1,000 + 300 + 90 = 206,371,390

I showed the answer to 206,371,390 if you want the answer to 20,637,139... Here you go:

20,000,000 + 600,000 + 30,000 + 7,000 + 100 + 30 + 9 = 20,637,139

kupik [55]3 years ago

4 0

The answer is 20000000+600000+30000+7000+100+30+9

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A complex electronic system is built with a certain number of backup components in its subsystems. One subsystem has eight ident

Fudgin [204]

Answer:

a) 0.0486 = 4.86% probability that exactly two of the four components last longer than 1000 hours.

b) 0.9996 = 99.96% probability that the subsystem operates longer than 1000 hours.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either they last more than 1,000 hours, or they do not. Components operate independently, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

One subsystem has eight identical components, each with a probability of 0.1 of failing in less than 1,000 hours.

So 1 - 0.1 = 0.9 probability of working for more, which means that $p = 0.9$

a. exactly two of the four components last longer than 1000 hours.

This is P(X = 2) when $n = 4$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.9)^{2}.(0.1)^{2} = 0.0486$

0.0486 = 4.86% probability that exactly two of the four components last longer than 1000 hours.

b. the subsystem operates longer than 1000 hours.

The subsystem has 8 components, which means that $n = 8$

It will operate if at least 4 components are working correctly, so we want:

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{8,0}.(0.9)^{0}.(0.1)^{8} \approx 0$

$P(X = 1) = C_{8,1}.(0.9)^{1}.(0.1)^{7} \approx 0tex][tex]P(X = 2) = C_{8,2}.(0.9)^{2}.(0.1)^{6} \approx 0$

$P(X = 3) = C_{8,3}.(0.9)^{3}.(0.1)^{5} = 0.0004$

Then

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0 + 0 + 0.0004 = 0.0004$

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.0004 = 0.9996$

0.9996 = 99.96% probability that the subsystem operates longer than 1000 hours.

5 0

3 years ago

What is the length of FG?

kodGreya [7K]

Answer:

B. 4

Step-by-step explanation:

If Triangle ABC is congruent to Triangle EFG, then A = E, B = F, and G = C.

In this case, we want to find FG. BC is congruent to FG. Therefore, FG is 4 inches.

5 0

2 years ago

Daniella is solving 8/9 divided by 4. find her mistake and correct it.

Korolek [52]

Answer:

the answer is 2/9.

Step-by-step explanation:

8/9÷4

= 8/9 × 1/4

= 8/36

=2/9

6 0

3 years ago

There are 32 forwards and 80 guards in Leo's basketball league.Leo must include all players on a team and wants each team to hav

jeka94

Answer: There are 5 guards on each team.

Step-by-step explanation:

Since we have given that

Number of forwards in basketball league = 32

Number of guards in basketball league = 80

We need to find the greatest number of teams possible.

We will find "H.C.F. of 32 and 80.

Since H.C.F. of 32 and 80 = 16

Number of guard would be

$\dfrac{80}{16}=5$

Hence, there are 5 guards on each team.

7 0

3 years ago

A pastry shop earned $9,026 over the course of 5 days. How much did they earn on just 1 day? Note: do not write a dollar sign

o-na [289]

Answer:

9207

Step-by-step explanation:

because if you multiply

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3 years ago