The answer should be the 3rd one.
The line has a gradient of -5 and an intercept of -9.
so on a graph it would go 5 down and 9 across (towards the left of the graph)
Hi there!
We can use right-triangle trigonometry to solve.
We are given the HYPOTENUSE and ADJACENT sides, so we must use cosine in this instance.
cosθ = Adjacent/Hypotenuse
We can plug in what is given:
cos(28) = A/17
Solve for 'A':
17cos(28) = <u>15.01 ft</u>
You dont have anything that we can answer to.
<h2>
Quadratic Function Equations</h2>
To find the equation of a parabola given the vertex and the zeroes, we can use the intercept form equation to help us:
- r and s = intercepts/zeros of the graph
<h2>Solving the Question</h2>
We're given:
- Zeros: -8, 4
- Maximum: (-2, 18)
⇒ Plug in the given information:
<h2>Answer</h2>
