Qual o resultado de (-3+4-2)elevado a 5

Question is in screenshot. Please answer it correctly

fomenos

a) You need to sell 12 or 29 dresses.

b) Any number between 2 and 39 dresses will give a positive profit.

<h3>How many dresses must be sold in order to make a profit of 3000 euros?</h3>

Here we know that the profit, in euros, as a function of the number of dresses sold is:

P(x) = -11*x^2 + 450*x - 800

Now, if you want to find how many dresses you need to sell to have a profit of 3000 euros, then you need to solve:

P(x) = 3000 = -11*x^2 + 450*x - 800

So we need to solve the quadratic equation:

-11x^2 + 450x - 800 - 3000 = 0

-11x^2 + 450x - 3800 = 0

The solutions are given by Bhaskara's formula:

x = (-450 ± √(450^2 - 4*(-3800)*(-11))/2*(-11)

x = (-450 ± 187.9)/(-22)

We have two solutions that give the same profit:

x = (-450 + 187.9)/-22 = 11.9 that can be rounded to 12.
x = (-450 - 187.9)/-22 = 28.99 that can be rounded 29.

Then if you sell either 12 or 29 dresses, you will get a profit of 3000 euros.

b) To make a profit you need to sell more than P = 0, so let's solve that first:

P= 0 = -11*x^2 + 450*x - 800

The solutions are:

x = (-450 ± √(450^2 - 4*(-800)*(-11))/2*(-11)

x = (-450 ± 409)/(-22)

The smaller solution is:

x = (-450 + 409)/-22 = 1.86 that can be rounded to 2.

(because you can't sell 1.86 of a dress)

The other solution is:

x = (-450 - 409)/-22 = 39

So, between 2 and 39 dresses, you will make a profit.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

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6 0

1 year ago

Please help due in 10 minutes

noname [10]

The right answer is 4

6 0

3 years ago

According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann

mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable Y is defined as the number of consecutive time intervals in which the water supply remains below a critical value y₀.

The random variable Y follows a Geometric distribution with parameter p = 0.409.

The probability mass function of a Geometric distribution is:

$P(Y=y)=(1-p)^{y}p;\ y=0,12...$

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

$P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844$

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

$=(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780$

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable Y as follows:

$\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445$

Compute the standard deviation of the random variable Y as follows:

$\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88$

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

= P (Y ≥ 3.325)

= P (Y ≥ 3)

= 1 - P (Y < 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2)

$=1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064$

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0

3 years ago

Greatest common factor of −27x2yz5 + 15x3z3

dimulka [17.4K]

The GCF will be found as follows:
-27x^2yz^5+15x^3z^3
-27x^2yz^5=-3*3*3*x*x*y*z*z*z*z*z
15x^3z^3=3*5*x*x*x*z*z*z
the GCF is the product of the lowest power of each factor that appears in each term
thus we shall have:
3*z*z*z*x*x
=3z^3x^2

8 0

3 years ago

The selling price of an item is $650 marked up from the wholesale cost of $450. Find the percent markup from wholesale cost to s

Blababa [14]

Answer:

The markup percentage is 30.76 %

Step-by-step explanation:

Given as :

The selling price of an item = s.p = $650

The wholesale price of an item = w.p = $ 450

Let The markup percentage = d %

Now, According to question

d % = $\dfrac{\textrm selling price - \textrm whole sell price}{\textrm whole sell price}$

Or, d = $\dfrac{\textrm s.p - \textrm w.p}{\textrm w.p}$ × 100

Or, d = $(\frac{650-450}{450})\times 100$

Or, d = $\frac{200}{650}$ × 100

Or, d = 30.7 5

The markup percentage = d = 30.76 %

Hence The markup percentage is 30.76 % Answer

7 0

3 years ago