Answer:
(- 1, 2)
Step-by-step explanation:
Given a quadratic in standard form y = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= -
f(x) = x² + 2x + 3 ← is in standard form
with a = 1 and b = 2, hence
= -
= - 1
Substitute x = - 1 into f(x) for corresponding value of y
f(- 1) = (- 1)² + 2(- 1) + 3 = 1 - 2 + 3 = 2
vertex = (- 1, 2 )
Answer: Option A. The solution set is (4,5)
Step-by-step explanation:
Solve the equation for<em> </em>y to obtain the form of the equation of the line.
You have:
y=-x+9 (The slope is -1 and the y-intercept is 9)
y=x+1 (The slope is 1 and the y-intercept is 1)
When you graph it you obtain the graph shown in the figure attached.
The solution is the intersection of the lines.
Then, the solution set is (4,5)
Answer:
The first option
Step-by-step explanation:
The domain of a rational function should be all real numbers except for when the denominator is equal to 0. To find when the denominator is equal to 0 you simply need to find the zeroes of the denominator... but in this case you can do that through factoring and using the quadratic equation.
So first step is going to be to factor out the GCF, which in this case is x. This gives you the equation. . So one of the zeroes is when x=0. Now to find the other two zeroes you can use the quadratic equation which is
. So to find the other zeroes you simply plug the values in. a=2, b=-1, c=-15