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3 years ago

A parallelogram has angles of 80, 100, 80 and 100 degrees. What is it?

Mathematics

1 answer:

olchik [2.2K]3 years ago

5 0

It is a parallelogram because the opposite sides, 100 and 80, add up to 180.

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Find the coordinates of the figure after the transformations.

kaheart [24]

Zzzzzzzzzzzzzzzzzzzzzzzzz

7 0

3 years ago

A large high school offers AP Statistics and AP Calculus Among the seniors in this school 65% take AP Statistics, 45% take AP Ca

Igoryamba

Answer:

0.8

Step-by-step explanation:

P(AP statistics) = 65%

P(AP Calculus) = 45%

P(AP statistics n AP Calculus) = 30%

Probability of AP statistics or AP Calculus but not both :

Probability of event A or B :

P(AUB) = p(A) + p(B) - p(AnB)

P(AP statistics U AP Calculus) = P(AP statistics) + P(AP Calculus) - P(AP statistics n AP Calculus)

= 0.65 + 0.45 - 0.30

= 0.8

= 80%

4 0

2 years ago

Robert's dog is 4 years older than Karen's cat. In 3 years, the sum of the ages of Robert's dog and Karen's cat will be 13. How

mylen [45]

Answer:

5.5 years old.

Step-by-step explanation:

Let D represent present age of Robert's dog and C represent present age of Karen's cat.

We have been given that Robert's dog is 4 years older than Karen's cat. We can represent this information in an equation as:

$D=C+4...(1)$

We are also told that in 3 years, the sum of the ages of Robert's dog and Karen's cat will be 13. After 3 years age of dog and cat would be $D+3$ and $C+3$ respectively.

We can represent this information in an equation as:

$D+3+C+3=13...(2)$

From equation (1), we will get:

$C=D-4$

Upon substituting this value in equation (2), we will get:

$D+3+D-4+3=13$

Combine like terms:

$2D+2=13$

$2D+2-2=13-2$

$2D=11$

$\frac{2D}{2}=\frac{11}{2}$

$D=5.5$

Therefore, Robert's dog is 5.5 years old right now.

3 0

3 years ago

Choose all of the equations that have the solution x = -

padilas [110]

Answer:

x - = answer: x = +

x - = - answerx = - +

x + = - answer x = -

+x = answer x =

x - = - answer x = - +

the only equation is x + = -

4 0

3 years ago

4tan^2 x-8tanx+3=0 on interval [0,2pi]

Vadim26 [7]

$\bf 4tan^2(x)+8tan(x)+3=0\qquad [0,2\pi ]
\\\\\\
\textit{since it's just a quadratic, we'll just factor it}
\\\\\\\
[2tan(x)+1][2tan(x)+3]=0\implies 
\begin{cases}
2tan(x)+1=0\\
\qquad tan(x)=-\frac{1}{2}\\
\qquad \measuredangle x=tan^{-1}\left( -\frac{1}{2} \right)\\
\qquad \measuredangle x\approx 333.4^o, 153.4^o\\
2tan(x)+3=0\\
\qquad tan(x)=-\frac{3}{2}\\
\qquad \measuredangle x=tan^{-1}\left(-\frac{3}{2} \right)\\
\qquad \measuredangle x\approx303.7^o, 123.7^o
\end{cases}$

7 0

3 years ago