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Sergeu [11.5K]
3 years ago
5

For what value of the number k is the following function differentiable at x=2

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
7 0

Answer:

For f(x) to be differentiable at 2, k = 5.

Step-by-step explanation:

For f(x) to be differentiable at x = 2, f(x) has to be continuous at 2.

For f(x) to be continuous at 2, the limit of f(2 – h) = f(2) = f(2 + h) as h tends to 0.

Now,

f(2 – h) = 2(2 – h) + 1 = 4 – 2h + 1 = 5 – 2h.

As h tends to 0, lim (5 – 2h) = 5

Also

f(2 + h) = 3(2 + h) – 1 = 6 + 3h – 1 = 5 + 3h

As h tends to 0, lim (5 + 3h) = 5.

So, for f(2) to be continuous k = 5

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Step-by-step explanation:

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a). A(-6, -4), B(-3, -1)

Distance between A and B = \sqrt{(-6+3)^2+(-4+1)^2}

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b). C(3.5, 1), D(-4, 2.5)

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                                              = \sqrt{58.5}

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