Question

a regulation tennis court for a double match is laid out so that it's length is 6 ft more than two times its width. the area of a doubles court is 2808 square feet what is the length and width of the singles Court

Answer 1

Area=LW
L=6+2W

given
A=2808

subsitute
2808=LW
subsitute 6+2W for L
2808=(6+2W)(W)
2808=2W²+6W
divide both sides by 2
1404=W²+3W
minus 1404 from both sides
0=W+3W-1404
farctor, what 2 numbers multiply to get -1404 and add to get 3
-36 and 39
0=(W-36)(W+39)
set each to zero

0=W-36
36=W

0=W+39
-39=W
false, can't have negative dimentions

W=36
L=6+2W
L=6+2(36)
L=6+72
L=78

the length is 78ft
the width is 36ft
0=