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Strike441 [17]
3 years ago
8

You have a solution that either contains Pb(NO3)2 or KNO3. You add a solution of NaCl and observe no change in the solution. Whi

ch compound did the original solution contain? Explain your answer.
Chemistry
1 answer:
Naddika [18.5K]3 years ago
3 0

The compound originally contained KNO₃ solution.

Explanation:

When a mixture which contains either Pb(NO₃)₂ or KNO₃ is added with NaCl solution, no reaction takes place. This confirms the presence of KNO₃ in the solution.

The reason behind the above activity can be attributed to the lower placement of Na (sodium) in reactivity charge than potassium (K). Hence, it cannot displace Potassium (K) from the aqueous KNO₃ solution. Whereas the NaCl reacts with Pb(NO₃)₂ to produce white insoluble precipitate of PbCl₂. This confirms the presence of KNO₃ in solution.  

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When 25.0 grams of solid potassium hydroxide (KOH, molar mass = 56.1 g/mol) is dissolved in 100.0 grams of water, the solution i
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Answer:

They gave you the equation; Cp=,

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Explanation:

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2.00 L of a gas is collected at 25.0°C and 745.0 mmHg. What is the volume at 760.0 mmHg
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1.7960L

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Why doesn't the density of the object change when you adjust the mass and volume of the objects?
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If the a of a monoprotic weak acid is 1. 2×10^−6. What is the [H] of a 0. 31 m solution of this acid?
Vanyuwa [196]

The pH of the solution of the given acid is 3.099

Let  HX  be the weak acid:

HX ⇌  H^{+}+ X^{-}

For which:

K_{a} = [ H^{+}][ X^{-}] / [HX]

If  K_{a} lies in the range 10^{-4} - 10^{-10}we can assume that the equilibrium concentrations used in the expression are a good enough approximation to the initial concentrations.

Rearranging and taking negative logs of both sides gives:

pH = \frac{1}{2} [pK_{a} - loga]

a is the concentration of the acid.

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pH = \frac{1}{2} [5.69- (-0.508)]

pH = 3.099

Learn more about pH of acid here;

brainly.com/question/13043236

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2 years ago
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