Answer:
a) Approximate boiling point of HBr = -60.15 °C
b) Approximate boiling point of AsH₃ = -52.25 °C
Explanation:
Döbereiner stated that some elements could be arranged in groups of 3 similar elements ( known as "triads) , and the element of the middle ( elements are ordered with respect to their atomic mass) would have properties between the other 2 ( the average value)
a) In the first case the triad would be the halogen triad ( Cl , Br and I ) . And according to Döbereiner , the boiling point of HBr should be the average of HCl and HI . Therefore
Approximate boiling point of HBr = [(- 84.9°C) + (-35.4°C)]/2 = -60.15 °C
b) Simmilarly for AsH₃ , PH₃ and SbH₃ , the boiling point of AsH₃ would be
Approximate boiling point of AsH₃ = [(- 87.4°C) + (-17.1°C)]/2 = -52.25 °C
Answer:
The tetanus vaccine is a dose of the bacterium Clostridium Tetani, in inactive form or even a surface molecule that helps the body to actively form the antibody.
The tetanus vaccine has coverage for life, it is mandatory in those countries where the disease became common, such as the USA, Argentina, Chile, Uruguay among others.
Before a surgical act or a suspicion of exposure with this bacterium, the booster of the tetanus vaccine should be administered quickly.
Explanation:
Tetanus disease generates a tetanization of all the muscles of the organism, generating spasmodic contractions, which make it impossible to function and develop life when it affects the diaphragm as it makes breathing impossible.
Tetanization does not affect differently in age or sex, it only consists of contamination with the bacteria to be sufficient.
The sources of contagion are areas of mud or earth, rusty cutting or sharp elements, and poorly hygienic or abandoned areas. In order for the bacteria to be transmitted or the transmission route to be fulfilled, there must be a lesion of loss of continuity of the epithelium or mucosa.
A) Magnesium Chloride
Mg is the symbol of Magnesium and Cl is the symbol of chlorine ( but when Cl is a compound it will be Choride)
54.0 ml of a 1.2 m solution was diluted to a total volume of 228 ml
USing dilution equation
M1V1 = M2V2
Where M1V1 is before dilution while M2V2 is after dilution.
Therefore;
M1= 1.20 M, V2= 54 ml,
M2= V2 = 228 ml
1.20 M × 54 ml = M2 × 228 ml
M2 = (1.2 ×54)/ 228 ml
= 0.2842 M
0.2842 × 114 ml = M2 × (114 +111)
M2 = (0.2842 ×114)/ 225
= 0.143995
= 0.144 M
Answer:
x is HCl because pH = 2 (acid and it reacted with Mg plus it turned litmus paper to red)
y is NaOH because pH = 10 (base and turned litmus paper to blue)
z is NaCl because pH = 7 (neutral and no reaction to litmus paper and Mg)
