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Ulleksa [173]
2 years ago
10

An ice skater moves back and forth on an ice rink. She speeds up on the straight portion of the rink. She slows down near each e

nd of the rink and then turns around. Which claim supported by evidence?
Chemistry
1 answer:
andrey2020 [161]2 years ago
6 0

The options are;

A) The skater experiences acceleration both while skating in a straight line and while making her turn.

B) Because the skater does not change her direction or speed, she does not experience acceleration.

C) The skater only experiences acceleration when she is turning.

D) The skater only experiences acceleration while skating in a straight line.

Answer:

A: The skater experiences acceleration both while skating in a straight line and while making her turn

Explanation:

We are told that She speeds up on the straight portion of the rink. This means that she experienced an acceleration since the speed was not constant but gradually increasing.

Also, we are told that She slows down near each end of the rink and then turns around. This means that she reduced speed before turning and it means there was also an acceleration as well when making the turn.

Thus, she experience acceleration both in the straight line and when making turn.

Option A is correct

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Answer:

\large \boxed{\text{0.012 mol}}  

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

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For simplicity in writing , let's call p-toluidine hydrochloride A and N-acetyl-<em>p</em>-toluidine B.

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1. Moles of A

\text{Moles of A} = \text{70. mL A}\times \dfrac{\text{0.167 mmol A}}{\text{1 mL A}}= \text{12 mmol A}

2. Moles of B

The molar ratio is 1 mol B:1 mol A

Moles of B = moles of A = 12 mmol = 0.012 mol

\text{You can prepare $\large \boxed{\textbf{0.012 mol}}$ of N-acetyl-p-toluidine. }

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