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Ulleksa [173]
2 years ago
10

An ice skater moves back and forth on an ice rink. She speeds up on the straight portion of the rink. She slows down near each e

nd of the rink and then turns around. Which claim supported by evidence?
Chemistry
1 answer:
andrey2020 [161]2 years ago
6 0

The options are;

A) The skater experiences acceleration both while skating in a straight line and while making her turn.

B) Because the skater does not change her direction or speed, she does not experience acceleration.

C) The skater only experiences acceleration when she is turning.

D) The skater only experiences acceleration while skating in a straight line.

Answer:

A: The skater experiences acceleration both while skating in a straight line and while making her turn

Explanation:

We are told that She speeds up on the straight portion of the rink. This means that she experienced an acceleration since the speed was not constant but gradually increasing.

Also, we are told that She slows down near each end of the rink and then turns around. This means that she reduced speed before turning and it means there was also an acceleration as well when making the turn.

Thus, she experience acceleration both in the straight line and when making turn.

Option A is correct

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What was one way John Dalton was wrong about the structure of matter?
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Be sure to answer all parts. A mixture of CO2 and Kr weighs 47.9 g and exerts a pressure of 0.751 atm in its container. Since Kr
ololo11 [35]

Answer:a)  Mass of CO_2 in mixture = 26.3 grams

b) Mass of Kr in mixture that can be recovered= 21.5 grams

Explanation:

Given :

Total Pressure = pressure of krypton + pressure of carbon dioxide = 0.751 atm

pressure of krypton = 0.231 atm

Thus pressure of carbon dioxide = 0.751 - 0.231 =0.52 atm

As we know:

p=x\times P

where,

p = partial pressure

P = total pressure = 0.751 atm

x = mole fraction

For CO_2

x_{CO_2}=\frac{p_{CO_2}}{P}=\frac{0.52}{0.751}=0.70

{\text {Mass of} CO_2}=moles\times {\text {Molar mass}}=0.70\times 44=30.8g

For Kr

x_{Kr}=\frac{p_{Kr}}{P}=\frac{0.231}{0.751}=0.30

{\text {Mass of} Kr}=moles\times {\text {Molar mass}}=0.30\times 84=25.2g

Total mass = Mass of CO_2 + Mass of krypton = 30.8 + 25.2 = 56 g

Percentage of CO_2=\frac{30.8}{56}\times 100=55\%

a) Thus Mass of CO_2 in mixture =\frac{55}{100}\times 47.9=26.3g

Percentage of Kr=\frac{25.2}{56}\times 100=45\%

b) Thus Mass of Kr in mixture that can be recovered=\frac{45}{100}\times 47.9=21.5g

7 0
3 years ago
Restaurant​ a's chicken salad contains the same number of grams of fat as the chicken salad of restaurant
german
To compute for grams of fat in each salad:

We know that, A = C.

And B is 5 grams more, so it is B = 5 + A

And the total fat is 65, so A + B + C = 65 grams.


Computation:

A + (5 + A) + A = 65

3A + 5 = 65

3A = 60

A = 20

A = 20

B = (65 - 40) = 25

C = 20
6 0
3 years ago
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