Question

A 4.5 liter sample of a gas at 2 atm and 300 K has 0.80 mole of gas. If 0.35 mole of the gas is added to the sample at the same temperature and pressure, what is the volume of the gas?
3.9 liters
5.3 liters
6.3 liters
6.5 liters​

Answer 1

Answer:

6.5 liters​.

Explanation:

• We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

• If P and T are constant, and have different values of n and V:

(V₁n₂) = (V₂n₁)

• Knowing that:

V₁  = 4.5 L, n₁ = 0.80 mol,

V₂  =  ??? L, n₂ = 0.35 + 0.80 = 1.15 mol.

• Applying in the above equation

(V₁n₂) = (V₂n₁)

∴ V₂ = (V₁n₂)/n₁ = (4.5 L)(1.15 mol)/(0.8 mol) = 6.469 L ≅ 6.5 L.

So, the right choice is: 6.5 liters​.