Answer:
V = 296.6 liters of oxygen.
Explanation:
The reaction of combustion of sulfur is:
O₂(g) + S(s) → SO₂(g)        (1)
To find the volume of the oxygen we need to use the Ideal Gas Law:
 (2)
   (2)
Where:
V: is the volume
 : is the number of moles of oxygen
: is the number of moles of oxygen
R: is the gas constant = 0.082 L*atm/(K*mol)
T: is the temperature = 273 K (at STP)
P: is the pressure = 1 atm (at STP)
So we need to find the number of moles of oxygen that reacts with sulfur:

Where:
 : is the number of moles of sulfur
: is the number of moles of sulfur
m: is the mass of sulfur = 425 g
M: is the molar mass of sulfur = 32.065 g/mol                                                                            

From reaction (1) we have that 1 mol of O₂ reacts with 1 mol of S, hence the number of moles of oxygen is:
 
   
Finally, the volume of oxygen is (equation (2)):

Therefore, are necessary 296.6 liters of oxygen for the combustion of sulfur.
              
I hope it helps you!